如何在C#中处理复杂的json值 [英] How do I process complex json value in C#
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问题描述
您好b
$ b有人可以帮助我处理下面的Json字符串值,请突出显示parseValue中的数据,如Message.ID,Message.Version,Message.Val .ValMessage.optionalAdditionalData.data。
{no:194,id:011049150083,parseValue:[{Message.ID:1,Message.Version: 2,Message.Val.ValMessage.optionalAdditionalData.data:F2A51}]};
感谢您的回复
我尝试过:
我无法处理的值是标记为
Message.ID,Message.Version
解决方案
查看序列化和反序列化Json
Json反序列化
使用 JSON.NET [ ^ ],您需要使用 JsonProperty属性 [ ^ ]指定属性名称。
例如:
public class ParseValue
{
[JsonProperty( Message.ID)]
public string MessageId { get ; set ; }
[JsonProperty( Message.Version)]
public string MessageVersion { get ; set ; }
[JsonProperty( Message.Val.ValMessage.optionalAdditionalData.data)]
public string MessageAdditionalData { get 跨度>; set ; }
}
public class Root
{
[JsonProperty( no)]
public string 否{ get ; set ; }
[JsonProperty( id)]
< span class =code-keyword> public string ID { get ; set ; }
[JsonProperty( parseValue)]
< span class =code-keyword> public ParseValue [] ParseValue { get ; set ; }
}
...
根数据= JsonConvert.DeserializeObject< Root>(jsonString);
有关JSON反序列化的其他信息,请查看此深入文章,该文章基于此处提出的问题汇总在一起:在C#中使用JSON& VB [ ^ ]
Hi Can you please someone help me to process the below Json string value, Please highlight the data inside parseValue like Message.ID, Message.Version , Message.Val.ValMessage.optionalAdditionalData.data. {"no":"194","id":"011049150083","parseValue":[{"Message.ID":"1","Message.Version":"2","Message.Val.ValMessage.optionalAdditionalData.data":"F2A51"}]}"; Appreciate your response
What I have tried:
I am not able to process the value which is marked as
Message.ID, Message.Version
解决方案
Look at Serializing and Deserializing the Json
Json Deserialize
Using JSON.NET[^], you would need to use the JsonProperty attribute[^] to specify the property name.
For example:
public class ParseValue { [JsonProperty("Message.ID")] public string MessageId { get; set; } [JsonProperty("Message.Version")] public string MessageVersion { get; set; } [JsonProperty("Message.Val.ValMessage.optionalAdditionalData.data")] public string MessageAdditionalData { get; set; } } public class Root { [JsonProperty("no")] public string No { get; set; } [JsonProperty("id")] public string Id { get; set; } [JsonProperty("parseValue")] public ParseValue[] ParseValue { get; set; } } ... Root data = JsonConvert.DeserializeObject<Root>(jsonString);
For additional information on JSON deserialization, check out this in-depth article that was put together base on questions asked here: Working with JSON in C# & VB[^]
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