如何在php表中获取mysql数据 [英] how get mysql data in php table
本文介绍了如何在php表中获取mysql数据的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
浏览器窗口：
连接到MySQL
连接数据库
注意：未定义变量：link在C：\ xampp\htdocs \globall \ members.php第23行
警告：mysql_query（）期望参数2为资源，给定为null在C：\ xampp\htdocs \globall \ members.php第23行
这是第23行
$ result = mysql_query（$ query，$ link）
Browser window:
Connected to MySQL
Connected to Database
Notice: Undefined variable: link in C:\xampp\htdocs\globall\members.php on line 23
Warning: mysql_query() expects parameter 2 to be resource, null given in C:\xampp\htdocs\globall\members.php on line 23
this is line 23
$result = mysql_query($query,$link)
<?php
mysql_connect("localhost", "admin", "") or die(mysql_error());
echo "Connected to MySQL<br />";
mysql_select_db("globall") or die(mysql_error());
echo "Connected to Database";
$query = " SELECT user_name, mobile " .
"FROM customer ";
echo "<br>" ;
$result = mysql_query($query,$link)
or die(mysql_error());
// this will count the total user in database
$num_users = mysql_num_rows($result);
$table_header =<<<EOD
<h2><center>GLoBALL Users Database </center></h2>
<table width="100%" border="1" cellpadding="2" cellspacing="2" align="center">
<tr>
<th>Username</th>
<th>Mobile</th>
</tr>
EOD;
$user_details = '';
while ($row = mysql_fetch_array($result)) {
$user_name = $row['user_name'];
$mobile = $row['mobile'];
$user_details .=<<<EOD
<tr>
<td>$user_name</td>
<td>$mobile</td>
</tr>
EOD;
$user_details .=<<<EOD
<tr>
<td> </td>
<td>Total : $num_users</td>
</tr>
EOD;
}
?>
推荐答案
result = mysql_query（
result = mysql_query(
查询，
链接）
link)
<?php
mysql_connect("localhost", "admin", "") or die(mysql_error());
echo "Connected to MySQL<br />";
mysql_select_db("globall") or die(mysql_error());
echo "Connected to Database";
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