在C中结束这个嵌套循环 [英] End this nested loop in C.

问题描述

#include <stdio.h> 
#include <limits.h> 
int main () 
{ 
  /* variable definition: */ 
  char StudentName[100];
  char end;
  float ExamValue, Sum, Avg; 
  int students,exams; 
   // Loop through Students 
  for (students=1; students <INT_MAX ; students++)
  { 
     // reset Sum to 0 
     Sum =0.0;   
     printf("Enter Student Name \n"); 
     scanf("%s", StudentName);    
     // Nested Loop for Exams 
    for (exams=0; exams < 3; exams++)
    { 
        printf ("Enter exam grade: \n"); 
        scanf("%f", &ExamValue); 
        Sum += ExamValue;
    }    
    Avg = Sum/3.0; 
    printf( "Average for %s is %f\n",StudentName,Avg);
	if (StudentName == 'end')
	break;
}
  return 0; 
}

我的尝试：



我已经尝试了各种版本，但仍然没有。

What I have tried:

I have tried various versions of this and still nothing.

推荐答案

这甚至都不会编译，因为最后的if语句不正确。

That will not even compile because the if statement at the end is incorrect.

if (StudentName == 'end')
break;

您无法以这种方式比较字符串，并且您正在尝试比较字符数组，而不是单个字符。字符串 end 也必须是双引号。替换为以下内容：

You cannot compare strings in this way, and you are trying to compare a character array, not a single character. Also the string end must be in double quotes. Replace it with the following:

if (strcmp(StudentName, "end") == 0)
break;

首先正确地缩进你的代码，所以它看起来不像是一个虚假的大括号：

Start by indenting your code correctly so it doesn't look like it ends with a spurious close curly bracket:

#include <stdio.h> 
#include <limits.h> 
int main () 
{ 
  /* variable definition: */ 
  char StudentName[100];
  char end;
  float ExamValue, Sum, Avg; 
  int students,exams; 
  // Loop through Students 
  for (students=1; students <INT_MAX ; students++)
  { 
    // reset Sum to 0 
    Sum =0.0;   
    printf("Enter Student Name \n"); 
    scanf("%s", StudentName);    
    // Nested Loop for Exams 
    for (exams=0; exams < 3; exams++)
    { 
      printf ("Enter exam grade: \n"); 
      scanf("%f", &ExamValue); 
      Sum += ExamValue;
    }    
    Avg = Sum/3.0; 
    printf( "Average for %s is %f\n",StudentName,Avg);
    if (StudentName == 'end')
    {
      break;
    }
  }
  return 0; 
}

现在我要看的是将函数中的退出测试提高，这是你做的第一件事：

Now what I would look at is moving the "exit test" higher in the function, so that it's the first thing you do:

#include <stdio.h> 
#include <limits.h> 
int main () 
{ 
  /* variable definition: */ 
  char StudentName[100];
  char end;
  float ExamValue, Sum, Avg; 
  int students,exams; 
  // Loop through Students 
  for (students=1; students <INT_MAX ; students++)
  { 
    printf("Enter Student Name \n"); 
    scanf("%s", StudentName);    
    if (strcmp(StudentName, "end") == 0)
    {
      break;
    }
    Sum =0.0;   
    for (exams=0; exams < 3; exams++)
    { 
      printf ("Enter exam grade: \n"); 
      scanf("%f", &ExamValue); 
      Sum += ExamValue;
    }    
    Avg = Sum/3.0; 
    printf( "Average for %s is %f\n",StudentName,Avg);
  }
  return 0; 
}

如果这不能解决您的问题，那么您需要更详细地解释您正在做什么，而不是您没想到的，或者没有这样做。您已经做了些什么来找出原因 - 包括调试器在您的代码运行时向您显示的内容。

If that doesn't fix your problem, then you need to explain in a lot more detail exactly what it is doing that you didn't expect, or not doing that you did. And what you have done to find out why - including what the debugger showed you while your code was running.

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