Java.lang.arrayindexoutofboundsexception：java编译中的3个错误 [英] Java.lang.arrayindexoutofboundsexception:3 error in java compilation

问题描述

您好，我正在尝试使用冒泡排序对2d数组程序进行排序但是当我编译程序时，它运行到程序的特定部分，它打印出2d数组，但是，当它到达排序部分时，我收到一个错误，java.lang.Arrayindexoutofboundsexception：3。请告诉我如何摆脱这个错误。请参阅下面的代码。



我尝试过：

Hello, I am trying to sort 2d array program using bubble sort but when I compile the program, it runs to the specific part of the program, It prints out the 2d array, But, when it reaches to the sorting part, I get an error, "java.lang.Arrayindexoutofboundsexception:3". Please tell me how to get rid of this error. See the code below.

What I have tried:

import java.util.Random;
import java.util.Scanner;

public class arrays {

	public static void main(String[] args) {
		
		Random ran= new Random();
	
		Scanner scan = new Scanner(System.in);
		
		int num,secnum,temp,i,j,k;
		
		System.out.println("Please enter a num.");
		
		
		
		num= scan.nextInt();
		
		System.out.println("Please enter another value.");
		
		secnum = scan.nextInt();
		
		int arrayi[][] = new int[num][secnum];
		
		
		for( i =0; i< num ; i++) {
			
			for( j =0; j< secnum; j++) {
				
				arrayi[i][j]= ran.nextInt(100);
				
			}
		}
		
		System.out.println("The array is below:");
		
for(i =0; i< num ; i++) {
			
			for( j =0; j< secnum; j++) {
				
				System.out.print(arrayi[i][j] + " ");
				
			}
			System.out.println();
		}
for( i =0; i< num ; i++) {
	
	for( j =0; j< secnum; j++) {
		
	for( k=0; k <secnum; k++) {
		if(arrayi[i][k] > arrayi[i][k+1] ) {
			temp = arrayi[i][k];
			arrayi[i][k] = arrayi[i][k+1];
			arrayi[i][k+1] = temp;
		}
	}
		
	}
	
}
System.out.println("Sorted array is below:");
for( i =0; i< num ; i++) {
	
	for( j =0; j< secnum; j++) {
		
		System.out.print(arrayi[i][j] + " ");
		
	}
	System.out.println();
}
		
scan.close();
	}
	

}

推荐答案

for( k=0; k < secnum; k++) {
    if(arrayi[i][k] > arrayi[i][k+1] )

array [i] 的长度是 secnum 。因此，您可以访问的最大索引是 secnum - 1 。



当循环到达最后一次迭代时， k = secnum - 1 ，因此您无法访问 arrayi [i] [k + 1] ，因为这是在外面数组的界限。



（你可以通过使用调试器轻松找到它。）



将你的循环改为：

The length of array[i] is secnum. Therefore, the maximum index you can access is secnum - 1.

When your loop reaches the final iteration, k = secnum - 1, so you cannot access arrayi[i][k + 1], because that is outside the bounds of the array.

(You could have easily found this out for yourself by using the debugger.)

Change your loop to:

for ( k=0; k < secnum - 1; k++) {

这篇关于Java.lang.arrayindexoutofboundsexception：java编译中的3个错误的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！