使用带有正斜杠的正则表达式查找字符串 [英] Find a string using regex with forward slashes in it

问题描述

如何在下面的示例中找到带有正则表达式的字符串，以dd300开头并以逗号结尾（结果包含逗号）？





示例字符串：

dd301 / 122/4454，dd300 / 122/300，NR45，



预期成果：

dd300 / 122/300，



我的尝试：



可以获得以下匹配dd300，但需要知道如何包含正斜杠并停在逗号处。



（？<！\w）dd300

How do I find the string with a Regular Expression in the example below that start with 'dd300' and end with a comma (result to include the comma)?


Example string:
dd301/122/4454,dd300/122/300,NR45,

Expected Result:
dd300/122/300,

What I have tried:

Can get the following to match dd300, but need to know how to include forward slashes and stop at the comma.

(?<!\w)dd300

推荐答案

像斜线一样的特殊字符必须用反斜杠转义。



要匹配特定字符，请使用。* 或。+ 后跟该字符。因为那些贪心（这个术语应该由每个正则表达式tuturioal处理），附加一个？。



所以最终的正则表达式可能是：

Special characters like the slash must be escaped with a back slash.

To match until a specific character occurs use .* or .+ follwed by that character. Because those are greedy (the term should be handled by every regex tuturioal), append a ?.

So the final regex might be:

(dd300\/.+?,)

括号只是当你需要访问匹配的字符串时需要。



根据你的输入，你也可以使用更具体的正则表达式。例如，如果 dd300 总是以两个斜线分隔的数字表示，则可以是

The parentheses are only necessary when you need to access the matched string.

Depending on your input you may also use a more specific regex. If for example the dd300 is always follwed by two slash separated numbers it can be

(dd300\/\d+\/\d+,)

其中 \d 指定与使用相同的任何数字[0-9] 。

最基本的就是：

dd300.*?,

哪个是''dd300';后跟任何字符，任意数量的重复，尽可能少;然后是逗号。



如果你要去使用正则表达式，然后获取 Expresso 的副本[ ^ ] - 它是免费的，它会检查并生成正则表达式。

Which is "'dd300'; followed by any character, any number of repetitions, as few as possible; then a comma".

If you are going to work with regexes, then get a copy of Expresso[^] - it's free, and it examines and generates Regular expressions.

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