如何将100添加到数组元素列表中 [英] How do I add 100 to a list of array elements

问题描述

第4行：我无法弄清楚如何使anArray数组在for循环中的索引0之后为每个元素添加100？说明在评论中。有什么建议吗？

 public static void main（String [] args）{
 // LINE 1. DECELARE INTRAY INTEGERS 
 int [] anArray; 
 
 // LINE 2.为阵列中的10个INTEGERS分配内存。 
 anArray = new int [10]; 
 
 //创建输入设备的可用实例
 Scanner myInputScannerInstance = new Scanner（System.in）; 
 
 //我们会要求用户输入一个整数。请注意，在本练习中，
 //代码我们无法验证用户是否实际
 //输入INTEGER或不是。在生产程序中，我们需要
 //来验证这一点;例如，通过包含
 //异常处理代码。 （按原样，用户可以键入XYZ 
 //，这将导致异常。）
 System.out.print（输入一个整数并按回车：）; 
 
 //将用户输入（以字符串形式输入，甚至
 //虽然我们要求用户输入一个整数）转换为整数
 int myFirstArrayElement = Integer.parseInt （myInputScannerInstance.next（））; 
 
 // LINE 3.使用CONVERTED INTEGER初始化第一个阵列元素myFirstArrayElement 
 anArray [0] = myFirstArrayElement; 
 
 // LINE 4.通过将每个元素添加100来初始化第二个元素。 
 //示例：第二元素的价值是第一元素的价值100; 
 //第三元素的价值是第二元素的价值100;等等。 
 for（int j = 0; j< anArray.length; j ++）{
 if（anArray [j]！= anArray [0]）{
 anArray [j] + = 100 ; 
} 
 
} 
 
 
 // LINE 5.根据顶级模型显示阵列中每个元素的价值-OF-CODE评论。 
 Arrays.sort（anArray）; //发送我们的Anarray数组，按sort（）方法按升序排序
 int i; //定义循环的计数器。我们可以这样做或者在
 // for for循环中，就像我们在前面的for循环中所做的那样。 
 
 for（i = 0; i< anArray.length; i ++）{//循环，从0开始，每次加1，直到计数器小于数组长度。 
 System.out.println（索引处的元素+ i +：+ anArray [i]）; //打印数字
} 
 
} 
 
} 

我的尝试：



我已为代码完成了其他所有工作。我无法弄清楚第4行。请帮忙。谢谢。

解决方案

下面的内容应该这样做。从1开始，因为第3行用输入值初始化了索引0。然后根据你的要求，array [1] = index [0] + input或anArray [0]等等......

  for （ int  j = 1; j< anArray.length; j ++）{
 anArray [j] = anArray [j-  1 ] + anArray [ 0 ]; 
} 

输出：

输入一个整数并点击返回：100

索引0的元素：100

索引1：200的元素

索引2的元素：300

索引为3的元素：400

元素在指数4：500

元素在指数5：600

元素在指数6：700

元素在索引7：800

元素在索引8：900

元素在索引9：1000

  for （ int  j = 1; j< anArray.length; j ++）
 {
 anArray [j] = anArray [j-  1 ] +  100 ;  //   j是当前项目，（j-1）是前一项 
} 

On line 4: I can not figure out how to make the anArray array add 100 to each element following index 0 in the for loop? The instructions are in the comment. Any suggestions?

public static void main(String[] args) {
        // LINE 1. DECLARE AN ARRAY OF INTEGERS
        int[] anArray; 
        
        // LINE 2. ALLOCATE MEMORY FOR 10 INTEGERS WITHIN THE ARRAY.
        anArray = new int[10];
        
        // Create a usable instance of an input device
        Scanner myInputScannerInstance = new Scanner(System.in); 
        
        // We will ask a user to type in an integer. Note that in this practice
        // code  WE ARE NOT VERIFYING WHETHER THE USER ACTUALLY
        // TYPES AN INTEGER OR NOT. In a production program, we would
        // need to verify this; for example, by including
        // exception handling code. (As-is, a user can type in XYZ
        // and that will cause an exception.)
        System.out.print("Enter an integer and hit Return: ");
        
        // Convert the user input (which comes in as a string even
        // though we ask the user for an integer) to an integer
        int myFirstArrayElement = Integer.parseInt(myInputScannerInstance.next());
        
        // LINE 3. INITIALIZE THE FIRST ARRAY ELEMENT WITH THE CONVERTED INTEGER myFirstArrayElement
        anArray[0] = myFirstArrayElement;
        
        // LINE 4. INITIALIZE THE SECOND THROUGH THE TENTH ELEMENTS BY ADDING 100 TO THE EACH PRECEDING VALUE.
        // EXAMPLE: THE VALUE OF THE SECOND ELEMENT IS THE VALUE OF THE FIRST PLUS 100;
        // THE VALUE OF THE THIRD ELEMENT IS THE VALUE OF THE SECOND PLUS 100; AND SO ON.
        for (int j=0; j < anArray.length; j++) {
            if (anArray[j]!= anArray[0]){
                anArray[j] += 100;
            }
           
        } 

        
        // LINE 5. DISPLAY THE VALUES OF EACH ELEMENT OF THE ARRAY IN ASCENDING ORDER BASED ON THE MODEL IN THE TOP-OF-CODE COMMENTS.
        Arrays.sort(anArray);		// Send our Anarray array to be sorted in ascending order by the sort() method
        int i;				// Define the counter for the loop. We can do it this way or inside
                                        // the for loop, as we did in the preceding for loop.
                                        
        for (i=0; i < anArray.length; i++) {	// Loop, starting at 0 and adding 1 each time, until counter is less than array length. 		
              System.out.println("Element at index " + i + ": " + anArray[i]);// print the numbers
        }

    }
    
}

What I have tried:

I have done everything else for the code. I cant figure out line 4. please help. Thanks.

解决方案

Something like below should do it. Start with 1 because the line 3 initialized the index 0 with the input value. Then based on your requirement, array[1] = index[0] + input or anArray[0] , and so on...

for (int j=1; j < anArray.length; j++) {
    anArray[j] = anArray[j-1] +anArray[0];
}

Output:
Enter an integer and hit Return: 100
Element at index 0: 100
Element at index 1: 200
Element at index 2: 300
Element at index 3: 400
Element at index 4: 500
Element at index 5: 600
Element at index 6: 700
Element at index 7: 800
Element at index 8: 900
Element at index 9: 1000

for (int j=1; j < anArray.length; j++) 
{
  anArray[j] = anArray[j-1] + 100; // j is the current item, (j-1)  is the previous one
}

这篇关于如何将100添加到数组元素列表中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！