如何使用日期对目录中的文件和文件夹进行排序 [英] How can I sort files and folders in a directory using their date
问题描述
Hey Guys,
我正在寻找一个代码,我可以根据日期和名称对目录中的文件和文件夹(特别是文件)进行排序。就像假设我想先根据以S开头的名字对文件进行排序。之后,我想根据日期再次对这些已排序的文件进行排序。因此,我每天都可以获得相同日期的文件。
直到现在我已经根据他们的名字对文件进行了排序。但是如何根据日期排序文件,我无法理解。你能帮我一个示例代码吗?
我在下面的部分附上我的代码。
我有什么试过:
包数;
import java.io. *;
import java .util.ArrayList;
import java.util.List;
公共类Newcount2 {
public static void main(String [] args){
List< string> files = new ArrayList<>();
List< string> directories = new ArrayList<>();
List< string> smallScount = new ArrayList<>();
List< string> capScount = new ArrayList<>();
文件夹=新文件(目录路径);
文件[] listOfFiles = folder.listFiles();
for(int i = 0; i< listOfFiles.length; i ++){
if (listOfFiles [i] .isFile()){
files.add(listOfFiles [i] .getName());
} else if(listOfFiles [i]。 isDirectory()){
directories.add(listOfFiles [i] .getName());
}
}
//用大写字母S和小S划分文件。
System.out.println(带s和s的文件S.);
for(String file:files){
if(file.startsWith(s))
smallScount。 add(file);
if(file.startsWith(S))
capScount.add(file);
}
/ *系统。 out.println(文件列表:\ n ---------------);
for(String fName:files)System.out.println (fName);
System.out.println(\ n目录列表:\ n -------------- -------);
for(String dName:directories)System.out.println(dName); * /
/ * System.out.println(带有'S'的文件列表:\ n ---------------);
for (String fName:smallScount)System.out.println(fName); * /
/ *
System.out.println(具有Capital'S'的文件列表:\ n ---------------);
for(String fName:capScount)System.out.println(fName); * /
System.out.println(小'S'的文件数:\ n ---------------) ;
System.out.println(smallScount.size());
System.out.println(文件计数与资本'S':\ n ---------------);
System.out.println(capScount.size());
}
}
Hey Guys,
I am looking for a code in which I can sort files and folders (specifically files) in a directory based on their date and name. Like suppose i want to sort files based on their names starting with "S" first. After that I want to sort those sorted files once again based on their date. So that every day I can get the files of the same date.
Till now i have sorted files based on their names. But how to sort files based on their date, that i cant understand. Can you guys help me with a sample code?
I am attaching my code in the below section.
What I have tried:
package count;
import java.io.*;
import java.util.ArrayList;
import java.util.List;
public class Newcount2 {
public static void main(String[] args) {
List<string> files = new ArrayList<>();
List<string> directories = new ArrayList<>();
List<string> smallScount = new ArrayList<>();
List<string> capScount = new ArrayList<>();
File folder = new File("The directory Path");
File[] listOfFiles = folder.listFiles();
for (int i = 0; i < listOfFiles.length; i++) {
if (listOfFiles[i].isFile()) {
files.add(listOfFiles[i].getName());
} else if (listOfFiles[i].isDirectory()) {
directories.add(listOfFiles[i].getName());
}
}
//dividing the files with caps S and small S.
System.out.println("Files with s and S.");
for (String file : files) {
if(file.startsWith("s"))
smallScount.add(file);
if(file.startsWith("S"))
capScount.add(file);
}
/* System.out.println("List of files :\n---------------");
for(String fName: files) System.out.println(fName);
System.out.println("\nList of directories :\n---------------------");
for(String dName: directories) System.out.println(dName);*/
/* System.out.println("List of files with small 'S' :\n---------------");
for(String fName: smallScount) System.out.println(fName);*/
/*
System.out.println("List of files with Capital 'S' :\n---------------");
for(String fName: capScount) System.out.println(fName);*/
System.out.println("Count of files with small 'S' :\n---------------");
System.out.println(smallScount.size());
System.out.println("Count of files with Capital 'S' :\n---------------");
System.out.println(capScount.size());
}
}
推荐答案
使用数组。 sort()
(参见 Arrays(Java Platform SE 7) [ ^ ])Comparator(Java Platform SE 7) [ ^ ]。
你可以执行在您的原始listOfFiles
数组中排序或使用副本(如果必须保留)。
未经测试的示例区分文件和文件夹:
UseArrays.sort()
(see Arrays (Java Platform SE 7 )[^]) with a Comparator (Java Platform SE 7 )[^].
You can perform the sort on your orginallistOfFiles
array or use a copy if that must be preserved.
Untested example which does not differentiate between files and folders:
Arrays.sort(listOfFiles, new Comparator<File>(){
public int compare(File f1, File f2)
{
// Names beginning with 's' on top
boolean s1 = f1.getName().startsWith("s") || f1.getName().startsWith("S");
boolean s2 = f2.getName().startsWith("s") || f2.getName().startsWith("S");
if (s1 && !s2)
return -1;
if (s2 && !s1)
return -1;
// Everything else including both names beginning with 's' is sorted by date
return Long.valueOf(f1.lastModified()).compareTo(f2.lastModified());
} });
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