在powershell中，如何按目录名的长度对目录进行排序？ [英] In powershell how do sort directories by the length of the directory name?

问题描述

我已经阅读了很多示例，但似乎无法找到一个语法来按照完整目录名的长度对PowerShell中的目录列表进行排序。



这就是我所拥有的：

 $ folderNamePatterns = @（bin，obj）
 $ deleteFolderList = Get-ChildItem -Path $ rootFolder -Recurse -Directory -Include（$ folderNamePatterns）| Sort-Object -Property DirectoryName.Length 
写输出文件夹列表是：
 for（$ i = 0; $ i -lt $ deleteFolderList.Count; $ i ++）
 {
写输出$ deleteFolderList [$ i] .FullName 
} 

它没有错误，但它没有'排序清单。



我必须遗漏一些令人沮丧的简单事。谁能告诉我什么？



亲切的愿望~Patrick



我试过的：



我已经为-Property参数尝试过所有种类。

解决方案

folderNamePatterns = @（bin，obj）

deleteFolderList = Get-ChildItem -Path

rootFolder -Recurse -Directory -Include（

I've read plenty of examples but don't seem to be able to find a syntax to sort a list of directories in PowerShell by the length of the full directory name.

This is what I have:

$folderNamePatterns = @( "bin", "obj" )
$deleteFolderList = Get-ChildItem -Path $rootFolder -Recurse -Directory -Include ( $folderNamePatterns ) | Sort-Object -Property DirectoryName.Length
Write-Output "Folder list is:"
for( $i=0; $i -lt $deleteFolderList.Count; $i++ )
{
	Write-Output $deleteFolderList[ $i ].FullName
}

It gives no error but it doesn't sort the list.

I must be missing something frustratingly simple. Can anyone please tell me what?

Kind wishes ~ Patrick

What I have tried:

I've tried all sorts for the -Property argument.

解决方案

folderNamePatterns = @( "bin", "obj" )

deleteFolderList = Get-ChildItem -Path

rootFolder -Recurse -Directory -Include (

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