在javascript中将军事时间转换为标准时间的最佳方法 [英] Best way to convert military time to standard time in javascript
问题描述
将军事时间转换为上午和下午时间的最佳方式是什么? 。
我有以下代码并且工作正常:
What is the best way to convert military time to am and pm time. . I have the following code and it works fine:
$scope.convertTimeAMPM = function(time){
//var time = "12:23:39";
var time = time.split(':');
var hours = time[0];
var minutes = time[1];
var seconds = time[2];
$scope.timeValue = "" + ((hours >12) ? hours -12 :hours);
$scope.timeValue += (minutes < 10) ? ":0" : ":" + minutes;
$scope.timeValue += (seconds < 10) ? ":0" : ":" + seconds;
$scope.timeValue += (hours >= 12) ? " P.M." : " A.M.";
//console.log( timeValue);
}
但是当我运行程序时,我对输出节目不满意。 。
But I am not satisfied in the output shows when I run my program. .
样本输出:
20:00:00 8:0:0 P.M.
08:00:00 08:0:0 A.M
16:00:00 4:30:0 P.M.
我想实现如下输出:
20:00:00 8:00:00 P.M.
08:00:00 8:00:00 A.M
16:30:00 4:30:00 P.M.
那里有什么建议吗?谢谢
Is there any suggestions there? Thanks
推荐答案
当分钟<时,你错过了连接字符串10
和秒< 10
所以你没有得到理想的结果。
You missed concatenating the string when minutes < 10
and seconds < 10
so you were not getting the desired result.
使用 Number()$ c将字符串转换为数字$ c>并正确使用它,如下面的工作代码段所示:
Convert string to number using Number()
and use it appropriately as shown in the working code snippet below:
编辑:更新后的代码 Number()
声明小时
,分钟
和秒
。
Updated code to use Number()
while declaration of hours
, minutes
and seconds
.
var time = "16:30:00"; // your input
time = time.split(':'); // convert to array
// fetch
var hours = Number(time[0]);
var minutes = Number(time[1]);
var seconds = Number(time[2]);
// calculate
var timeValue;
if (hours > 0 && hours <= 12) {
timeValue= "" + hours;
} else if (hours > 12) {
timeValue= "" + (hours - 12);
} else if (hours == 0) {
timeValue= "12";
}
timeValue += (minutes < 10) ? ":0" + minutes : ":" + minutes; // get minutes
timeValue += (seconds < 10) ? ":0" + seconds : ":" + seconds; // get seconds
timeValue += (hours >= 12) ? " P.M." : " A.M."; // get AM/PM
// show
alert(timeValue);
console.log(timeValue);
阅读: Number()
| MDN
Read up: Number()
| MDN
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