构造函数参数的继承。 [英] Inheritance in parameters of constructor.

问题描述

基类是A，B，C，它们各自的子类是A1，B1，C1。



- >类构造函数使用两个参数。 （B和C）



喜欢，A（B * b，C * c）。



- > A1类构造函数使用两个参数B1和C1，我也想通过传递参数B和C同时调用一个构造函数。



我已经实现了它方式：A1（B * b，C * c，B1 * b1，C1 * c1）：A（b，c）。



- >但问题是我必须保留两份副本;像基地b和孩子b1。 在打电话之前我必须分别准备b和b1。

有没有更好的方法来实现它？



我尝试了什么： < br $> b $ b

试过：



A（B * b，C * c）。



尝试：

A1（B * b，C * c，B1 * b1，C1 * c1）：A（b，c ）。

Base Classes are A, B, C and their respective Child classes are A1, B1, C1.

-> A class constructor uses two parameters. (B and C)

Like, A (B *b, C *c).

-> A1 class constructor uses two parameters B1 and C1 and I also want to call A constructor at the same time with passing argument B and C.

I have implemented it by this way : A1 (B *b, C *c, B1 *b1, C1 *c1) : A(b,c).

-> But the problem here is I have to maintain two copies; Like base b and child b1. Before calling I have to prepare both b and b1 separately.
Is there any better way to implement it?

What I have tried:

Tried :

A (B *b , C *c).

Tried :
A1 (B *b, C *c, B1 *b1, C1 *c1) : A(b,c).

推荐答案

无需传递副本。只需将指向派生类的指针传递给基类A的构造函数：

There is no need to pass copies. Just pass the pointers to the derived classes to the constructor of your base class A:

class A1 : public A
{
public:
    A1(B1 *b1, C1 *c1) : A(b1, c1) {}
};

引用：

在打电话之前我必须分别准备b和b1。

有没有更好的方法来实现它？

Before calling I have to prepare both b and b1 separately.
Is there any better way to implement it?

No.

As b 和 b1 是单独的对象，你不能将 b 传递给 A 以任何其他方式......

（如果 b1 只是 b ，而不是传递 b1 ）

No.
As b and b1 are separate objects, you can not pass b to A in any other way...
(If b1 was only a cast of b, than it would be enough to pass b1)

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