如何在不实际访问URL的情况下在给定URL上执行PHP脚本？它可以在后面运行吗？ [英] How do I execute a PHP script on given url without actually visiting the url? Is it possible to run it in the back?

问题描述

我想写一个获取字符串的php函数，转到我想要的url，将字符串放入该url中的文本字段，提交它并返回提交后显示的文本。我迷路了，帮帮我。



我尝试过的事情：



$ html = curl_init（'www.thewebsiteiwanttorunmyscripton.com'）;

解决方案

html = curl_init（'www.thewebsiteiwanttorunmyscripton.com'）;

听起来您自动尝试在网站上填写表单，提交表单然后显示结果。我会检查网站的来源以查找相关字段，看看它在提交时的作用。



它看起来像这样：

 <  表格   方法  =  get    action   =  / action.php >  
 <  输入    type   =  text    name   =  field1 >  
 <   / form  >  

表单的方法（获取）标识您是否应该发出POST或GET请求。

表单的操作（/ action.php）将为您提供请求的URL。

输入的name（field1）将是参数的名称。

I want to write a php function which gets a string, goes to the url I want, puts the string in to a text field in that url, submits it and returns the text shown after submitting. I'm lost guys, help me.

What I have tried:

$html= curl_init('www.thewebsiteiwanttorunmyscripton.com');

解决方案

html= curl_init('www.thewebsiteiwanttorunmyscripton.com');

It sounds like you're automatically trying to fill a form on a website, submitting it and then showing the result. I would check the website's source to find the relevant field and see what it does on submitting.

It will look something like this:

<form method="get" action="/action.php">
  <input type="text" name="field1">
</form> 

The form's method ("get") identifies if you should do a POST or GET request.
The form's action ("/action.php") will give you the URL to request.
The input's name ("field1") will be the name of the parameter.

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