使用函数为PHP生成数字 [英] Using functions to generate numbers for PHP

问题描述

我在练习中遇到问题



创建一个程序，随机生成-​​3到3之间的数字并显示数字。如果数字为零，1和-1，程序也应该继续



当数字不是-1,0或1时，程序将显示Good Job ！否则，程序将显示无效





请让我理解这个编码!!



我尝试过：

Im having trouble with this exercise

Create a program that randomly generate numbers between -3 and 3 and display the number. The program should also continue if the numbers are zero, 1 and -1

When the numbers is not -1, 0 or 1, the program will display "Good Job!" otherwise, the program will display "invalid"


PLEASE MAKE ME UNDERSTAND THIS CODING!!

What I have tried:

echo "<h3> Activity 1: continue function </h3>";
$random = rand(-3,3){
  Echo "The random number is: $random";
  echo "<br>"

推荐答案

random = rand（-3,3）{
Echo 随机数为：

random = rand(-3,3){ Echo "The random number is:

random;
echo < br>

[更新，感谢 Mohibur Ra​​shid ]

你的意思是

[Updated, thanks to Mohibur Rashid]
Do you mean

while (true)
{

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