正则表达式的换行符 [英] line break on regular expressions

问题描述

我正在尝试替换2个标签之间的所有内容，但我无法构建正确的表达式。

I'm trying to replace everything between 2 tags, but I'm not able to build the right expression.

这就是我所做的： /< tag>（。* | \ n *）< / tag> /

我希望它能捕获任何字符，包括换行符。

I want it to capture any characters including line breaks.

这是我需要捕获的一个例子：

This is an example of what I need to capture:

 <tag>
       <div class="feed_title">Some Title</div>
       <div class="feed_content">Some text</div>
    </tag>

你们有些人能告诉我我做错了吗？

Can some of you tell me what I'm doing wrong?

以下是RegExr的链接以及内容的完整示例： http：// regexr .com？2t4n1

Here is a link to RegExr and a full example of what the content looks like: http://regexr.com?2t4n1

推荐答案

'#.#m'

m 表示MULTILINE，它使得点能够匹配newlines = line休息 \ n

The m means MULTILINE, it makes the point able to match the newlines=line breaks \n

编辑：

因为它已被锐化修正眼睛和好大脑，显然'＃。+＃s'

as it has been corrected by sharp eyes and good brain, it is evidently '#.+#s'

EDIT2：

正如Michael Goldshteyn所说，这应该有效

As Michael Goldshteyn said, this should work

$ch = '<tag>\s+<div class="feed_title">Some Title</div>\s+<div class="feed_content">Some text</div>\s+</tag>'

preg_match('#<tag>(.+?)</tag>#s',$ch,$match)

还有另一个解决方案，没有 s 标志，我认为：

There is another solution, without s flag, I think:

preg_match('#<tag>((.|\s)+?)</tag>#',$ch,$match)

但它更复杂

。

编辑3 ：

我认为$ ch 中 \s 的存在是无稽之谈。 \s 用于RE，而不是字符串。

I think that the presence of \s in $ch is a nonsense. \s is used in a RE, not in strings.

我写的是因为我认为它可能是空白或 \t 可以在< 标记> 之前和其他行的开头

I wrote that because I was thinking that it could be blanks or \t that could be before <tag> and at the beginning of other lines

\t 是用逃脱写的;这也不是在字符串中写 \s 的理由

\t is written with an escape; that's not a reason to write \s also in a string

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