在C中使用函数的问题 [英] Issue in using function in C
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问题描述
此代码中的问题是什么?
我有这个错误
what is the problem in this code?
I have this error
conflicting types for ‘random’void random(org select[size]){
< br $> b $ b
我的尝试:
What I have tried:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define size 4
typedef struct Org
{
int id[4];
char name[4][7];
}org;
struct buff
{
int bid[4];
char bname[4][7];
};
struct buff buf[3];
void random(org select[size]){
int i,j,r=0;
for (i=0; i< 3;i++){
r = (rand() % (4 - 0)) + 0;
for( j=0;j<6;j++){
buf[i].bid[j]= select[r].id[j] ;
strcpy(buf[i].bname[j], select[r].name[j]);
}}
for ( int i=0; i<4 ;i++){
for(int j=0;j<4;j++){
printf("bname %s bid = %d \n", buf[i].bname[j], buf[i].bid[j]);
}}
}
void main( )
{
int i,j;
org select[size];
sprintf(select[0].name[0],"hello1");
sprintf(select[0].name[1],"hello2");
sprintf(select[0].name[2],"hello3");
sprintf(select[0].name[3],"hello4");
sprintf(select[1].name[0],"2ello1");
sprintf(select[1].name[1],"2ello2");
sprintf(select[1].name[2],"2ello3");
sprintf(select[1].name[3],"2ello4");
sprintf(select[2].name[0],"3ello1");
sprintf(select[2].name[1],"3ello2");
sprintf(select[2].name[2],"3ello3");
sprintf(select[2].name[3],"3ello4");
sprintf(select[3].name[0],"4ello1");
sprintf(select[3].name[1],"4ello2");
sprintf(select[3].name[2],"4ello3");
sprintf(select[3].name[3],"4ello4");
sprintf(select[4].name[0],"tello1");
sprintf(select[4].name[1],"tello2");
sprintf(select[4].name[2],"tello3");
sprintf(select[4].name[3],"tello4");
printf(" Initial id :\n");
for(i=0;i<4 ;i++)
{
for(j=0;j< 4;j++)
{
// Rgene = (rand() % (5 - 1)) + 1;
select[i].id[j]= j;
}}
random(select);
}
推荐答案
random是c-library中的标准函数。使用不同的名称,如myRandom或randomize来解决它。
random is a standard function in the c-library. Use a different name, like myRandom or randomize to solve it.
您正试图从指向其第一个元素的指针访问该结构,因此它应该是:
You are trying to access the structure from a pointer to its first element, so it should be:
void random(org* select){
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