Rlot中的Plot.ly:x轴的不需要的字母排序 [英] Plot.ly in R: Unwanted alphabetical sorting of x-axis
问题描述
我试了几个小时,但我没能成功。我的数据框只是
I tried for hours, but I could not succeed. My data frame is simply
df <- as.data.frame(matrix(c("g","d","a","b","z",5,4,3,2,1),5,2))
library("plotly")
p <- plot_ly(data = df,x = ~V1,y = ~V2,type = "scatter",mode = "lines+markers") %>%
layout(title = "my title")
p
所以,这给了我
但我不想要x轴要按字母顺序排序,我只想按顺序保留订单并查看递减的图表。
But I don't want x axis to be sorted alphabetically, I just want to keep the order as it is and see a decreasing graph.
推荐答案
首先,矩阵只能保存一个类的数据。因此,您有一个字符串矩阵,您将转换为 data.frame
。因为默认情况下 stringAsFactors = TRUE
,您的字符矩阵将转换为 data.frame
factor
,其中默认情况下两列的级别已排序。字母顺序为 V1
,并按 V2
的递增顺序。
First of all, a matrix can only hold data of one class. Hence you have a matrix of strings that you are converting to a data.frame
. Because by default stringAsFactors = TRUE
, your character matrix is converted to a data.frame
of factor
's, where the levels of your two columns are by default sorted. Alphabetically for V1
and in increasing order for V2
.
如果您不希望直接修改数据以在源头解决问题 - 正如其他答案中所指出的那样,您可以使用 plotly
的 categoryorder =
layout()
中的参数,方式如下:
If you don't wish to modify the data directly to remedy the issue at the source - as pointed out in the other answers, you can altenatively use plotly
's categoryorder =
argument inside layout()
in the following way:
library(plotly)
xform <- list(categoryorder = "array",
categoryarray = df$V1)
plot_ly(data = df,
x = ~V1,
y = ~V2,
type = "scatter",
mode = "lines+markers") %>%
layout(title = "my title",
xaxis = xform)
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