将参数传递给promisejs $ q中的promise成功回调 [英] Passing parameters to promise's success callback in angularjs $q

问题描述

我意识到这是一个与此一个非常相似的问题。但在我的情况下，我仍然不清楚如何做到这一点。只需要一些成功回调的帮助。

I realize this is a very similar question to this one. But I'm still unclear on how to do it in my situation. Just need some help with a successful callback.

这是有效的：

function getStuff(accountNumber) {
    var logMessage = 'POST GetStuff';

    return $http.post(GetStuff, { custId: accountNumber })
        .then(log);
}

function log(response) {
    logger.debug(response);
    return response;
}

这就是我想要完成的事情：

This is what I want to accomplish:

function getStuff(accountNumber) {
    var logMessage = 'POST GetStuff';

    return $http.post(GetStuff, { custId: accountNumber })
        .then(log(response, logMessage);
}

function log(response, logMessage) {
    logger.debug(logMessage, response);
    return response;
}

推荐答案

您可以使用：

function getStuff(accountNumber) {
    var logMessage = 'POST GetStuff';

    return $http.post(GetStuff, { custId: accountNumber })
        .then(
           function success(response) {
               return log(response, logMessage);
           }
        );
}

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