语法错误意外TELSE [英] Syntax error unexpected TELSE
本文介绍了语法错误意外TELSE的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
<?php
$name = (isset($_POST['name']) && !empty($_POST['name'])) ? $_POST['name'] : "" ;
$lname = (isset($_POST['lastname']) && !empty($_POST['lastname'])) ? $_POST['lastname'] : "" ;
$email =(isset($_POST['email']) && !empty($_POST['email'])) ? $_POST['email'] : "" ;
$password = (isset($_POST['password']) && !empty($_POST['password'])) ? $_POST['password'] : "" ;
$id = (isset($_POST['id']) && !empty($_POST['id'])) ? $_POST['id'] : "" ;
$conn=mysql_connect("localhost","root","");
$db=mysql_select_db("Signup",$conn);
$query5="SELECT * from start";
$result=mysql_query($query5) or die(mysql_error());
while($row=mysql_fetch_array($result))
{
$id1=$row[0];
if($id1== $id){
echo '<script language="javascript">';
echo'alert("Signup Succesfully")';
echo'</script>';
}
}
else
{
echo '<script language="javascript">';
echo'alert("Sorry u r not doc")';
echo'</script>';
}
?>
我的尝试:
如何在php中解决这个错误............
What I have tried:
how to solve this error in php............
推荐答案
name =(isset(
name = (isset(
_POST ['name'])&&!empty(
_POST['name']) && !empty(
_POST ['name'] ))?
_POST['name'])) ?
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