C＃是否可以将点或位置转换为int？ [英] C# Is it possible to convert a point or location to an int?

问题描述

是否有可能在一个点或位置，因为这是iv尝试和失败



是否可以转换为点或位置到int。这就是我尝试但失败了。

Is it possible to int a point or location, coz this is what iv tried and failed

Is it possible to convert a point or location to an int. This is what I've tried but it failed.

int d = (206,362);

任何人都可以帮帮我吗？

Can anyone help me out?

推荐答案

您可以将它映射到十进制（如果组件 int 值不是太大），这是其核心和整数类型。



我会考虑用它中的两个值创建一个字符串，用空格字符分隔。

You could map it to a decimal (if the component int values aren't too big) which is, at its core, and integer type.

I would look into just making a string with the two values in it, separated by a space character.

适用于16位坐标，不大于：

Works for 16-bit coordinates, no larger:

int intPt = (x << 16) | (y);

提取x-coord：

To extract x-coord:

int x = (intPt & 0xFF00) >> 16;

和y-coord：

and y-coord:

int y = intPt & 0x00FF;

那说，我真的不推荐它。您到底想要做什么？

That said, I really wouldn't recommend it. What on earth are you trying to do?

在给定以下限制的情况下，您可以轻松地将点映射到int。点x和y分量也是int。 x的范围例如是[0..255]，y的范围也是[0..255]。然后通过以下方式计算点到int的映射：

You can easily map a point to an int given the following restrictions. The points x and y components are also int. The range of x is for example [0..255] and the range for y is also [0..255]. Then the mapping of the point to an int is calculated by:

//This code is pure pseudo code
//Declare the range and a point
Range r = new Range(0,255);
Point<int,int> aPoint = new Point<int,int>(50,60,r);

//Here we map the point to an int
int mappedPoint = aPoint.x + aPoint.y * (r.Upper + 1);

//Here we map the int back to a point
int x = mappedPoint % (r.Upper + 1);
int y = mappedPoint / (r.Upper + 1);
Point<int,int> mappedPointFromInt = new Point<int,int>(x, y); 

因此，鉴于观察到上述约束，确实可以进行映射。应该引入一个检查以确保映射的点适合int。



干杯！

So yes a mapping is indeed possible given that the above constraints are observed. A check should be introduced to make sure that the mapped point will fit into an int.

Cheers!

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