是否可以使用'和'& '或'与isupper和isdigit我正在尝试运行下面的代码，但它不起作用。 [英] Is it okay to use 'and' & 'or' with isupper and isdigit I'm trying to run the code below but it's not working.

问题描述

int main()
{
    char pass[8];
    printf("Enter your password: (Maximum 8 characters)");
    scanf("%c",pass);

    if(isdigit(pass[0])  &&  isdigit(pass[1])){
    printf("AKH");
    }

    return 0;
}

如果第一个或第二个字符是数字，我期待printf运行，但它只是适用于第一个角色。



我尝试过：



我尝试使用字符1和0进行OR而不是引用数组，它运行正常。我需要帮助

I'm expecting the printf to run if either the first or second character is a digit, but it only works for the first character.

What I have tried:

I tried doing the OR with characters '1' and '0' instead of referencing the array and it worked fine. Please I need help

推荐答案

尝试

Try

if((isdigit(pass[0]) || isdigit(pass[1])){

小心丢失'（代码中的'



&&是C表示法逻辑AND：如果两个部分都为真，则结果为真。

Be careful with missing '(' in your code

&& is C notation for logical AND: result is true if both part are true.

((isdigit(pass[0]) && isdigit(pass[1]))
// means
((isdigit(pass[0]) AND isdigit(pass[1]))

||是逻辑OR的C表示法：如果至少结果为真一部分是真的。

|| is C notation for logical OR: result is true if at least one part is true.

Quote：

我希望printf能够运行或第二个特征ter是一个数字，但它只适用于第一个字符。

I'm expecting the printf to run if either the first or second character is a digit, but it only works for the first character.

那是因为你只读一个字符：

That is because you are reading only one character:

scanf("%c",pass);

读取字符串的格式为％s，而％c 读取一个字符。所以你必须使用

The format to read strings is "%s" while "%c" reads a single character. So you have to use

scanf("%s",pass);

我是纠正了逻辑运算符，但问题出在％c上。将其更改为％s后，它可以正常工作。感谢您的回复

I've corrected the logic operator but the problem was with the %c. After changing it to %s it works fine. Thanks for the replies

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