C ++ CLI中的MOD和DIV [英] MOD and DIV in C++ CLI

问题描述

大家好！我是C ++ / CLI的菜鸟，我想问一个小问题：



我需要得到两个整数变量A和B的MOD和DIV ，



如何用正确的语法和 A = A（MOD）B和A = A（DIV）B 我应该在我的代码中添加一个特殊的标题才能使用它们！???谢谢

解决方案

％ - mod

/ - div

  int  i1 =  5 ％ 2 ;  //   i1 == 1  
  int  i2 =  5  /  2 ;  //   i2 == 2  

< blockquote>虽然Simon完全正确，但也有

 ldiv_t ldiv（long int numerator，long int denominator）; 

它将分子除以分子的整数商和余数作为 ldiv_t 类型的结构，这个结构有两个成员quot和rem。如果你需要这两个结果，调用ldiv会更有效率。



最好的问候

Espen Harlinn

Hi everyone! I am a noob in C++/CLI, I d like to ask a small question:

I need to get the MOD and the DIV of two integer variables A and B,

How can I do A=A(MOD)B and A=A(DIV)B in the right syntax and... should I add an special header to my code in order to use these!??? THANKS

解决方案

% - mod
/ - div

int i1 = 5 % 2; // i1 == 1
int i2 = 5 / 2; // i2 == 2

While Simon is entirely right there is also

ldiv_t ldiv ( long int numerator, long int denominator );

Which returns the integral quotient and remainder of the division of numerator by denominator as a structure of type ldiv_t, this structure has two members quot and rem. If you need both results calling ldiv is more efficient.

Best regards
Espen Harlinn

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