查找路径上的android的两个位置之间的映射 [英] Finding route on a map between two locations in android

问题描述

我建立一个应用程序，我需要找到2 locations.The用户之间的映射可以进入2处，即源和目标，他可以得到一个地图上的路由。 有人可以PLZ建议我如何着手dis.Is有一个教程，可以帮助我在这？ 感谢名单提前。

解决方案

 公共类MappzzActivity扩展MapActivity {
保护无效的onCreate（包savedInstanceState）{
    // TODO自动生成方法存根
    super.onCreate（savedInstanceState）;
    的setContentView（R.layout.mapp）;
    双src_lat = latPoint;
    双src_long = lngPoint;

    双dest_lat = 8.88056;
    双dest_long = 76.5917;
    的GeoPoint srcGeoPoint =新的GeoPoint（（INT）（src_lat * 1E6）
            （中间体）（src_long * 1E6））;
    的GeoPoint destGeoPoint =新的GeoPoint（（INT）（dest_lat * 1E6）
            （中间体）（dest_long * 1E6））;

    DrawPath（srcGeoPoint，destGeoPoint，Color.GREEN，图形页面）;

    。mapView.getController（）animateTo（srcGeoPoint）;
    mapView.getController（）setZoom（15）。

}

@覆盖
保护的布尔isRouteDisplayed（）{
    // TODO自动生成方法存根
    返回false;
}

私人无效DrawPath（SRC的GeoPoint，GeoPoint对象DEST，INT的颜色，
        图形页面mMapView01）{

    //连接到地图Web服务
    StringBuilder的urlString =新的StringBuilder（）;
    urlString.append（http://maps.google.com/maps?f=d&hl=en）;
    urlString.append（＆放大器; SADDR =）; //从
    urlString.append（Double.toString（（双）src.getLatitudeE6（）/ 1.0E6））;
    urlString.append（，）;
    urlString
            .append（Double.toString（（双）src.getLongitudeE6（）/ 1.0E6））;
    urlString.append（＆放大器; DADDR =）; //给
    urlString
            .append（Double.toString（（双）dest.getLatitudeE6（）/ 1.0E6））;
    urlString.append（，）;
    urlString
            .append（Double.toString（（双）dest.getLongitudeE6（）/ 1.0E6））;
    urlString.append（＆放大器，即= UTF8＆功放; 0安培; OM = 0＆放大器;输出= KML）;

    Log.d（XXX，URL =+ urlString.toString（））;

    //获取KML（XML）文档。并解析它得到的坐标（方向
    // 路线）。
    文档DOC = NULL;
    HttpURLConnection类的URLConnection = NULL;
    网址URL = NULL;
    尝试 {
        URL =新的URL（urlString.toString（））;
        的URLConnection =（HttpURLConnection类）url.openConnection（）;
        urlConnection.setRequestMethod（GET）;
        urlConnection.setDoOutput（真正的）;
        urlConnection.setDoInput（真正的）;
        urlConnection.connect（）;

        DocumentBuilderFactory的DBF = DocumentBuilderFactory.newInstance（）;
        DocumentBuilder的DB = dbf.newDocumentBuilder（）;
        文档= db.parse（urlConnection.getInputStream（））;

        如果（doc.getElementsByTagName（GeometryCollection的）的getLength（）＆GT; 0）{

            字符串路径= doc.getElementsByTagName（GeometryCollection的）
                    .item（0）.getFirstChild（）。getFirstChild（）
                    。.getFirstChild（）getNodeValue（）;

            Log.d（XXX，路径=+路径）;

            的String []对= path.split（）;
            串[] lngLat =双[0] .split（，）; // lngLat [0] =经度

            // SRC
            的GeoPoint startGP =新的GeoPoint（
                    （中间体）（Double.parseDouble（lngLat [1]）* 1E6），
                    （中间体）（Double.parseDouble（lngLat [0]）* 1E6））;
            mMapView01.getOverlays（）
                    。新增（新MyOverLay（startGP，startGP，1））;

            的GeoPoint GP1;
            的GeoPoint GP2 = startGP;
            的for（int i = 1; I＆LT; pairs.length;我++）{
                lngLat =对[I] .split（，）;
                GP1 = GP2;
                // 小心！对于GeoPoint对象，第一：纬度，第二：经度
                GP2 =新的GeoPoint（
                        （中间体）（Double.parseDouble（lngLat [1]）* 1E6），
                        （中间体）（Double.parseDouble（lngLat [0]）* 1E6））;
                mMapView01.getOverlays（）。增加（
                        新MyOverLay（GP1，GP2，2，颜色））;

                Log.d（XXX，对：+对[I]）;

            }
            。mMapView01.getOverlays（）增加（新MyOverLay（DEST，DEST，3））;

        }
    }赶上（MalformedURLException异常E）{

        e.printStackTrace（）;
    }赶上（IOException异常E）{

        e.printStackTrace（）;
    }赶上（的ParserConfigurationException E）{

        e.printStackTrace（）;

    }赶上（的SAXException E）{

        e.printStackTrace（）;
    }

}
}
 

I am building an app where i need to find the route on a map between 2 locations.The user can enter the 2 locations i.e the source and destination and he could get the route on a map. Can someone plz suggest me as how to proceed with dis.Is there a tutorial which could help me in this? Thanx in advance.

解决方案

  public class MappzzActivity extends MapActivity {
protected void onCreate(Bundle savedInstanceState) {
    // TODO Auto-generated method stub
    super.onCreate(savedInstanceState);
    setContentView(R.layout.mapp);
    double src_lat = latPoint;
    double src_long = lngPoint;

    double dest_lat = 8.88056;
    double dest_long = 76.5917;
    GeoPoint srcGeoPoint = new GeoPoint((int) (src_lat * 1E6),
            (int) (src_long * 1E6));
    GeoPoint destGeoPoint = new GeoPoint((int) (dest_lat * 1E6),
            (int) (dest_long * 1E6));

    DrawPath(srcGeoPoint, destGeoPoint, Color.GREEN, mapView);

    mapView.getController().animateTo(srcGeoPoint);
    mapView.getController().setZoom(15);

}

@Override
protected boolean isRouteDisplayed() {
    // TODO Auto-generated method stub
    return false;
}

private void DrawPath(GeoPoint src, GeoPoint dest, int color,
        MapView mMapView01) {

    // connect to map web service
    StringBuilder urlString = new StringBuilder();
    urlString.append("http://maps.google.com/maps?f=d&hl=en");
    urlString.append("&saddr=");// from
    urlString.append(Double.toString((double) src.getLatitudeE6() / 1.0E6));
    urlString.append(",");
    urlString
            .append(Double.toString((double) src.getLongitudeE6() / 1.0E6));
    urlString.append("&daddr=");// to
    urlString
            .append(Double.toString((double) dest.getLatitudeE6() / 1.0E6));
    urlString.append(",");
    urlString
            .append(Double.toString((double) dest.getLongitudeE6() / 1.0E6));
    urlString.append("&ie=UTF8&0&om=0&output=kml");

    Log.d("xxx", "URL=" + urlString.toString());

    // get the kml (XML) doc. And parse it to get the coordinates(direction
    // route).
    Document doc = null;
    HttpURLConnection urlConnection = null;
    URL url = null;
    try {
        url = new URL(urlString.toString());
        urlConnection = (HttpURLConnection) url.openConnection();
        urlConnection.setRequestMethod("GET");
        urlConnection.setDoOutput(true);
        urlConnection.setDoInput(true);
        urlConnection.connect();

        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        DocumentBuilder db = dbf.newDocumentBuilder();
        doc = db.parse(urlConnection.getInputStream());

        if (doc.getElementsByTagName("GeometryCollection").getLength() > 0) {

            String path = doc.getElementsByTagName("GeometryCollection")
                    .item(0).getFirstChild().getFirstChild()
                    .getFirstChild().getNodeValue();

            Log.d("xxx", "path=" + path);

            String[] pairs = path.split(" ");
            String[] lngLat = pairs[0].split(","); // lngLat[0]=longitude

            // src
            GeoPoint startGP = new GeoPoint(
                    (int) (Double.parseDouble(lngLat[1]) * 1E6),
                    (int) (Double.parseDouble(lngLat[0]) * 1E6));
            mMapView01.getOverlays()
                    .add(new MyOverLay(startGP, startGP, 1));

            GeoPoint gp1;
            GeoPoint gp2 = startGP;
            for (int i = 1; i < pairs.length; i++) {
                lngLat = pairs[i].split(",");
                gp1 = gp2;
                // watch out! For GeoPoint, first:latitude, second:longitude
                gp2 = new GeoPoint(
                        (int) (Double.parseDouble(lngLat[1]) * 1E6),
                        (int) (Double.parseDouble(lngLat[0]) * 1E6));
                mMapView01.getOverlays().add(
                        new MyOverLay(gp1, gp2, 2, color));

                Log.d("xxx", "pair:" + pairs[i]);

            }
            mMapView01.getOverlays().add(new MyOverLay(dest, dest, 3));

        }
    } catch (MalformedURLException e) {

        e.printStackTrace();
    } catch (IOException e) {

        e.printStackTrace();
    } catch (ParserConfigurationException e) {

        e.printStackTrace();

    } catch (SAXException e) {

        e.printStackTrace();
    }

}
}

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