如何定义在C中返回函数数组的函数数组？ [英] How do I define array of functions that return array of function in C?

问题描述

hi
i需要完成代码才能生效。

hi i need to complete the code so that this line will work.

f[0]()[0]();

如何定义f？



我尝试过：



这里是我试过的东西，但不知道继续

how can i define f ?

What I have tried:

here is somthing that i tried but dont know to continue

void(*a)(*f)(...)

推荐答案

[update]

没有 typedef ，符合OP请求：

[update]
Without typedef, conformant to OP request:

#include <stdio.h>

void f(){ printf("hello\n"); }
void (*pf[])()={ f };
void (**g())(){ return pf; }
void (**(*pg[])())() = { g };

int main()
{
  pg[0]()[0]();
}

[/ update]







尽可能疯狂......

[/update]



As crazy as it can be...

#include <stdio.h>

int add(int a, int b){return a+b;}
int sub(int a, int b){return a-b;}

typedef int (* INT_FUN)(int a, int b);

INT_FUN f[] = {add, sub};
INT_FUN g[] = {sub, add, sub};

INT_FUN * af (){ return f; }
INT_FUN * ag (){ return g; }

typedef INT_FUN * ( *ARR_FUN )();

int main()
{
  ARR_FUN a[] = {af, ag}; // array of functions returning array of functions...

  printf("%d\n", a[1]()[0](10,5)); // calls 'sub(10,5)'

  return 0;
}

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