我如何修复此代码它是alu代码 [英] How do i.can fix this code it is alu code

问题描述

#include <stdio.h>
#include <stdlib.h>
//defineOpCodes
int OR(int A, int B);
int  AddSub(int A,int B, int OpCode);
int mux(short In1, short In2, short Sel);
int AND(int A,int B);

int main(){
    #define OP_ADD 0x00
#define OP_SUB 0x01
#define OP_LEFT 0x02
#define OP_RIGHT 0x03
   int A = 0b0000000001111011;
   int B = 0b0000000001100100;
   int Result = 0;
   char operation[4];
printf ("Which operation would you like? ADD/SUB/OR/AND > ");
sscanf("%s",operation);
int opcode=0;
    if (operation == "ADD")
int OpCode = ADD( A, B);

 else
if(operation == "SUB")
int OpCode = SUB(A ,B);

else
 if(operation == "AND")
  OpCode = 0;

 else
if (operation == "OR")
 OpCode = 0;


   int z = AddSub(int A, int B, int OpCode);



     int AndOut = AND(int A,int B);
   int OrOut = OR(int A,int B);
   int MuxOut = mux(AndOut, OrOut, s0);
    int MuxOut2 = mux(MuxOut1,z, s1);

    return MuxOut2;



















}

// Input and Output Registers
 int A = 0;
int B = 0;
int Result = 0;

// Status registers
int Z = 0; // bitstring.Bits(uint=bytes, length=8)
int Ovf = 0;

// Arithemtic and Logical Unit
int  AddSub(int A,int B, int OpCode){
    if (OpCode == ADD)
        Sum = A + B;
    else
        Sum = A - B;

    //set up the Z flag. Ignore the Ovf right flag for now
    if (Sum == 0)
        Z = 1;
    else
        Z = 0;
    return Sum, Z;
}

// 2-to-1 Multiplexer
int mux(short In1, short In2, short Sel)
{
int Out;
if (Sel == 0)
Out = In1;
else
Out = In2;
return(Out);
}

// AND Gate
int AND(A, B){
    return A&B;
}
//OR Gate
int OR(A, B){
    return A|B;
    }

我的尝试：



我不知道有人可以帮助我的错误在哪里

What I have tried:

I don't know where is the mistake if someone can help me

推荐答案

你的代码充满了bug。你真的需要阅读 C 编程语言的教程。



程序的'编译'版本如下

Your code is full of bugs. You really need to read a tutorial on C programming language.

A 'compiling' version of your program follows

#include <stdio.h>
#include <string.h>

#define ADD 0
#define SUB 1

int or(int a, int b);
int and(int a, int b);
int addsub(int a, int b, int opcode);
int mux(int a, int b, int sel);

int global_z; // zero flag (as matter of fact you shouldn't use globals)

int main()
{
  int a = 0b0000000001111011;
  int b = 0b0000000001100100;
  int result;

  char operation[4];

  printf ("Which operation would you like? ADD/SUB/OR/AND > ");
  if  (! fgets(operation, 4, stdin) )
    return -1;


  if ( strcmp( operation, "ADD") == 0)
    result = addsub(a, b, ADD);
  else if ( strcmp( operation, "SUB") == 0)
    result = addsub(a, b, SUB);
  else if ( strcmp( operation, "OR") == 0)
    result = or(a,b);
  else if ( strcmp( operation, "AND") == 0)
    result = and(a,b);
  else
    printf("invalid operation %s\n", operation);
  
  printf("the result of the %s operation is %d\n", operation, result);
  printf("zero flag value = %d\n", global_z);
  
  int muxout0 = mux(a,b,0);
  int muxout1 = mux(a,b,1);
  printf("muxout0 = %d, muxout1 = %d\n",muxout0, muxout1);
  
  return 0;
}

int or(int a, int b)
{
  int r = a | b;
  global_z = r == 0 ? 1 : 0;
  return r;
}

int and(int a, int b)
{
  int r = a & b;
  global_z = r == 0 ? 1 : 0;
  return r;
}

int addsub(int a, int b, int opcode)
{
  int r;
  if ( opcode == ADD)
    r = a + b;
  else
    r = a - b;
  global_z = r == 0 ? 1 : 0;
  return r;
}

int mux(int a, int b, int sel)
{
  int r;
  r = sel == 0 ? a : b;
  global_z = r == 0 ? 1 : 0;
  return r;
}

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