Xmlhtt prequest返回401上的PhoneGap / android应用 [英] Xmlhttprequest returns 401 on phonegap/android application
本文介绍了Xmlhtt prequest返回401上的PhoneGap / android应用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我要访问通过我的PhoneGap / Android应用程序与xmlhtt prequest的服务网络,但低于返回code的状态是401。
VAR请求=新XMLHtt prequest();
request.open(GET,http://www.mysite.fr/api/customers/2,真正的);
request.onreadystatechange =功能(){
警报(状态为+ request.status);
如果(request.status == 200 || request.status == 0){
响应= request.responseXML.documentElement;
itemDescription = response.getElementsByTagName('姓')[0] .firstChild.data;
警报(itemDescription);
}
}
request.send();
谁能帮我解释错误或提供我一个解决方案?
解决方案
如果你的网站是由prestashop创建的,所以访问使用Xmlhtt prequest web服务时,request.open应该是这样的:
<$p$p><$c$c>request.open("GET","http://www.mysite.fr/api/customes/2?PHP_AUTH_USER="+PHP_AUTH_USER+"&ws_key="+ws_key,true);
与 PHP_AUTH_USER =和ws_ke = key_generated_by_the_webservice
I want to access to the service web via my PhoneGap/android application with xmlhttprequest, but the code below returns "Status is 401".
var request = new XMLHttpRequest();
request.open("GET","http://www.mysite.fr/api/customers/2",true);
request.onreadystatechange = function() {
alert("Status is "+request.status);
if (request.status == 200 || request.status == 0){
response = request.responseXML.documentElement;
itemDescription = response.getElementsByTagName('lastname')[0].firstChild.data;
alert ( itemDescription );
}
}
request.send();
Can anyone help me explaining the error or offering me a solution?
解决方案
if your website is created by prestashop, so to access the webservice using Xmlhttprequest, the request.open should be like this:
request.open("GET","http://www.mysite.fr/api/customes/2?PHP_AUTH_USER="+PHP_AUTH_USER+"&ws_key="+ws_key,true);
with: PHP_AUTH_USER="" and ws_ke=key_generated_by_the_webservice
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