使用日期时间计算年龄 [英] Calculate age using datetime

问题描述

我试图找出如果年龄介于两者之间我该怎么办，例如16-21。



我尝试了什么：



我有一个名为Person的课程。

  public   string 名称{获得;  set ; } 
  public   string 姓氏{ get ;  set ; } 
  public  DateTime年龄{获取;  set ; } 
} 
 

我试图找出确定某些值之间的年龄。所以我们说：

人：

姓名：Blah

姓：Nah

年龄：20岁/>


我试图创建一个if语句，如果年龄介于16到21之间，则说明

等等。



我怎么能这样做？



提前谢谢。

解决方案

看看这里：与年龄一起工作：它与TimeSpan不同！ [ ^ ]

实际上，你不应该有年龄 DateTime属性。它应该命名为 DateOfBirth （例如）。然后可以在您需要时从出生日算起年龄属性。

这样：

  public  DateTime DateOfBirth { get ;  set ; } 
 
  public   int 年龄
 {
 < span class =code-keyword> get  { return （DateTime.Today  -  DateOfBirth）.Days /  365 ; } 
} 

分析：

- （DateTime.Today - DateOfBirth）返回 TimeSpan 值。

- TimeSpan中的总天数除以一年中的平均天数年龄的近似值。



请注意，Age属性是只读的，因为每次调用属性getter时都会计算它。因此它总是返回当前年龄。



希望这会有所帮助。麻烦。

Hi,

I was trying to figure out how could I do something if age is between, for example 16-21.

What I have tried:

I have a class called Person.

    public string Name { get; set; }
    public string Surname { get; set; }
    public DateTime Age { get; set; }
}

I was trying to figure out to determine the age between certain values. So let's say that:
Person:
Name: Blah
Surname: Nah
Age: 20

I was trying to create an if statement saying
if age is between 16 and 21 do something etc.

How could I do that?

Thanks in advance.

解决方案

Have a look here: Working with Age: it's not the same as a TimeSpan![^]

Actually, you should not have an Age DateTime property. It should be named DateOfBirth (for example). The Age property can then be computed when you need it, from the date of birth.
This way:

public DateTime DateOfBirth { get; set; }

public int Age
{
   get { return (DateTime.Today - DateOfBirth).Days / 365; }
}

Analyze:
- (DateTime.Today - DateOfBirth) returns a TimeSpan value.
- The total number of days in the TimeSpan is divided by the average number of days in a year to give an approximation of the age.

Note that the Age property is read-only, as it is computed everytime the property getter is called. It thus always returns the current age.

Hope this helps. Kindly.

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