需要解决这个问题我想生成一个大小为N的字符串。 [英] Need solution to this problem I want to generate a string of size N.

问题描述

<pre>>>> import string
>>> import random
>>> def id_generator(size=6, chars=string.ascii_uppercase + string.digits):
...    return ''.join(random.choice(chars) for _ in range(size))
...
>>> id_generator()
'G5G74W'
>>> id_generator(3, "6793YUIO")
'Y3U'

我尝试过的事情：



到目前为止，我不知道需要你的帮助!!

What I have tried:

Non so far im stuck need your help !!

推荐答案

一种方法是使计数器变量在再次找到时增加最大数字索引的计数，否则如果找到新的最大数字则重置为1。部分伪代码如下所示：

One way is to have a counter variable to increment count of the index of the largest number when it is found again, else reset to 1 if a new largest number is found. Partial pseudo code look like this:

INITIALIZE largestCount = 0

Inside the loop to locate the next largest number:

if numbersList[ index ] == numbersList[ largest ]:
        largestCount += 1
        # other code
elif numbersList[ index ] > numbersList[ largest ]:
        largestCount = 1
        # other code

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