如何替换所有非字母数字字符&空格的空间？ [英] How do I replace all non-alphanumerical characters & spaces with empty spaces?

问题描述

如何更换所有非字母数字字符&空格的空格？



我有这个但它只删除空格，我希望它删除所有非字母数字字符：

How do I replace all non-alphanumerical characters & spaces with empty spaces?

I have this but it only removes spaces, I want it to remove all NON-alphanumerical characters:

str.replaceAll("\\W","")

提前感谢您的帮助！





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我尝试了什么：



str.replaceAll（\\\\，）





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Thank you for the help in advance!


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What I have tried:

str.replaceAll("\\W","")


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推荐答案

尝试以下正则表达式

Try the following regular expression

[^a-zA-Z0-9]+

示例如下

The example follows

echo "abc---012" | sed -e 's/[^0-9a-zA-Z][^0-9a-zA-Z]*/ /g'
#output
abc 012

FYI：。+相当于.. *

FYI: .+ is equivalent to ..*

[^a-zA-Z0-9]

示例如下

example follows

echo "abc---012" | sed -e 's/[^0-9a-zA-Z]/ /g'
#output
abc   012

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