为什么我的代码没有给出结果。它输入数字后按下输入它没有显示任何东西...... [英] Why my code is not giving the result. It input numbers the after pressing enter it does not show anything...

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问题描述

  #include   <   stdio.h  >  
int main()
{ int a,b,c;
printf( 输入数字值);
scanf( %d%d%d,& a,& b ,和C);
if ((a> b)&&(a> c))
{
if (b> c)
printf( no为降序排列%d%d%d,a,b,c);
else
printf( 不按降序排列%d%d%d,a,c,b);

}
其他 如果((b> a)& ;&(b&c; c))
{如果(a> c)
printf( 不按降序排列%d%d%d,b,a,c);
else
printf( 不按降序排列%d%d%d,b,c,a);

}
其他 如果((c> a)& ;&(c> b))
{如果(a> b)
printf( 不按降序排列%d%dd,c,a,b);
else
printf( 不按降序排列%d%d%d,c,b,a);
}
return 0 ;
}





我的尝试:



  #include    <   stdio.h  >  
int main()
{ int a,b,c;
printf( 输入数字值);
scanf( %d%d%d,& a,& b ,和C);
if ((a> b)&&(a> c))
{
if (b> c)
printf( no为降序排列%d%d%d,a,b,c);
else
printf( 不按降序排列%d%d%d,a,c,b);

}
其他 如果((b> a)& ;&(b&c; c))
{如果(a> c)
printf( 不按降序排列%d%d%d,b,a,c);
else
printf( 不按降序排列%d%d%d,b,c,a);

}
其他 如果((c> a)& ;&(c> b))
{如果(a> b)
printf( 不按降序排列%d%dd,c,a,b);
else
printf( 不按降序排列%d%d%d,c,b,a);
}
return 0 ;
}

解决方案

尝试:

 scanf(< span class =code-string> %d%d%d,& a,& b,& c);  //  删除格式字符串末尾的额外空格 


您的代码不处理您平等的情况。

示例: a = b> c



建议:使用调试器查看代码正在做什么,用它来检查变量并确保任何内容都是它应该。



有一个工具可以让你看到你的代码在做什么,它的名字是调试器。它也是一个很好的学习工具,因为它向你展示了现实,你可以看到哪种期望与现实相符。

当你不明白你的代码在做什么或为什么它做它做的时候,答案就是答案是调试器

使用调试器查看代码正在执行的操作。只需设置断点并查看代码执行情况,调试器允许您逐行执行第1行并在执行时检查变量。



调试器 - 维基百科,免费的百科全书 [ ^ ]



掌握Visual Studio 2010中的调试 - 初学者指南 [ ^ ]

使用Visual Studio 2010进行基本调试 - YouTube [ ^ ]

调试器在这里向您展示您的代码正在做什么,您的任务是与什么进行比较应该这样做。

调试器中没有魔法,它没有找到错误,它只是帮助你。当代码没有达到预期的效果时,你就会接近一个错误。


#include<stdio.h>
int main()
{int a,b,c;
 printf("enter value of numbers ");
  scanf("%d %d %d ", &a,&b,&c);
  if((a>b)&&(a>c))
   {
   	if(b>c)
   	printf("no in descending order are %d %d %d",a,b,c);
   	else
   	printf("no in descending order are %d %d %d",a,c,b );
   	
   }
  else if((b>a)&&(b>c))
   { if(a>c)
     printf("no in descending order are %d %d %d",b,a,c);
     else
     printf("no in descending order are %d %d %d",b,c,a);
     
   }
   else if((c>a)&&(c>b))
   { if(a>b)
    printf("no in descending order are %d %d d",c,a,b);
    else
    printf("no in descending order are %d %d %d ",c,b,a);
   }
return 0;   
}



What I have tried:

#include<stdio.h>
int main()
{int a,b,c;
 printf("enter value of numbers ");
  scanf("%d %d %d ", &a,&b,&c);
  if((a>b)&&(a>c))
   {
   	if(b>c)
   	printf("no in descending order are %d %d %d",a,b,c);
   	else
   	printf("no in descending order are %d %d %d",a,c,b );
   	
   }
  else if((b>a)&&(b>c))
   { if(a>c)
     printf("no in descending order are %d %d %d",b,a,c);
     else
     printf("no in descending order are %d %d %d",b,c,a);
     
   }
   else if((c>a)&&(c>b))
   { if(a>b)
    printf("no in descending order are %d %d d",c,a,b);
    else
    printf("no in descending order are %d %d %d ",c,b,a);
   }
return 0;   
}

解决方案

Try:

scanf("%d %d %d", &a,&b,&c); // remove the extra space at the end of format string


Your code do not handle the case where you have equality.
Example: a = b > c

Advice: use the debugger to see what your code is doing, use it to inspect the variables and make sure that anything is as it should.

There is a tool that allow you to see what your code is doing, its name is debugger. It is also a great learning tool because it show you reality and you can see which expectation match reality.
When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.

Debugger - Wikipedia, the free encyclopedia[^]

Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]
Basic Debugging with Visual Studio 2010 - YouTube[^]
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.


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