坚持这个请帮助 [英] Stuck on this please help
本文介绍了坚持这个请帮助的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
定义一个函数,它将m和n整数作为输入并在m和n之间打印奇数
vector< int > oddNumbers( int m, int n)
{
}
我的尝试:
vector< int> oddNumbers( int l, int r)
{
oddNumbers 。推回();
cout<< 输入第二个数字;
oddNumbers.push_back();
for ( unsigned int i = l + 1; i< r; i ++)
{
if (i%2!= 0 )
oddNumbers.push_back()
cin>> i;
}
解决方案
如果你必须填写建议的功能,即
Quote:vector< int> oddNumbers(int m,int n)
{
}
然后
vector< int > oddNumbers( int m, int n)
{
vector< int> v;
if (m% 2 == 0 )++ m;
while (m< = n)
{
v.push_back(m);
m + = 2 ;
}
return v;
}
你不需要这样的向量作为返回。代码应该很简单:
void printOddNumbers( int l, int r)
{
for (< span class =code-keyword> int i = l; i< r; i ++)
{
if ( i% 2 == 0 )
{
cout<<一世;
}
}
}
该代码仅在r>湖如果l<可以考虑做什么错误处理或修复。 r。
建议:使用适当的缩进来查看代码结构,它有助于阅读并可以突出显示一些问题。参见cin
。
vector< int> oddNumbers( int l, int r)
{
oddNumbers 。推回();
cout<< 输入第二个数字;
oddNumbers.push_back();
for ( unsigned int i = l + 1; i< r; i ++)
{
if (i%2!= 0 )
oddNumbers.push_back()
cin>> i;
}
}
代码中的问题:
vector< int> oddNumbers( int l, int r)
{
< span class =code-comment> // 你在哪里定义/声明了oddNumbers?
oddNumbers.push_back(); // 你必须知道想要推回的价值
cout<< < span class =code-string> 输入第二个数字; // 第二个数字?
oddNumbers.push_back(); // 你必须知道想要推回的价值
< span class =code-keyword> for ( unsigned int i = l + 1 ; i< r; i ++)
{
if (i%2!= 0 )
oddNumbers.push_back() // a;在这里缺失
// 你要输出我
// 因为没有使用{},cin不在测试中
cin>> ;一世;
}
// 您的代码不会返回任何内容。
}
Define a function that takes m and n integers as input and print odd numbers between m and n
vector < int > oddNumbers(int m,int n)
{
}
What I have tried:
vector <int> oddNumbers(int l,int r)
{
oddNumbers.push_back();
cout<<"Enter second number";
oddNumbers.push_back();
for(unsigned int i=l+1;i<r;i++)
{
if (i%2!=0)
oddNumbers.push_back()
cin>>i;
}
解决方案
If you have to fill the proposed function, namely
Quote:vector < int > oddNumbers(int m,int n)
{
}
Then
vector < int > oddNumbers(int m,int n) { vector<int> v; if ( m % 2 == 0) ++m; while ( m <= n ) { v.push_back(m); m+=2; } return v; }
You dont need such vector as return. The code should really be easy:
void printOddNumbers(int l, int r) { for( int i = l; i < r; i++) { if( i % 2 == 0 ) { cout << i; } } }
The code only work if r > l. Think what error handling or "healing" to do, if l < r.
Advice: use proper indentation to see code structure, it helps reading and can highlight some problems. See thecin
.
vector <int> oddNumbers(int l,int r) { oddNumbers.push_back(); cout<<"Enter second number"; oddNumbers.push_back(); for(unsigned int i=l+1;i<r;i++) { if (i%2!=0) oddNumbers.push_back() cin>>i; } }
Problems in your code:
vector <int> oddNumbers(int l,int r) { // where did you defined/declared oddNumbers ? oddNumbers.push_back(); // you have to tell what value to want to push back cout<<"Enter second number"; // which second number ? oddNumbers.push_back(); // you have to tell what value to want to push back for(unsigned int i=l+1;i<r;i++) { if (i%2!=0) oddNumbers.push_back() // a ; is missing here // you want to output i // because of not using {}, the cin is not in test cin>>i; } // you code do not return anything. }
这篇关于坚持这个请帮助的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文