逐步调试以autoexec宏开头的访问应用程序 [英] Debug step by step an access application that starts with an autoexec macro

问题描述

Hello Everybody：正如我在上一个问题中提到的，我正在使用Access应用程序，并且在加载数据库时收到错误消息。



错误号是2950.它发生在宏Autoexec运行时，它尝试执行函数的代码（其中的第一个）。



我想（我之前从未使用过这个平台）我可以调试所涉及的函数代码的执行流程，一步一步地跟着它，就像我在Visual Basic或Excel中通常那样，但我不能在这里。我认为在内部查看代码也许我可以看到autoexec失败的原因，我无法从源代码运行应用程序。我想我有一个安装问题，但我需要看看它在哪里打破以及为什么。



是否可以按照一步一步的步骤执行从autoexec宏开始的Access应用程序？



我尝试过：



我在第一个涉及的函数中的第一个可执行代码行中设置了一个断点，但是流量永远不会到达那个点，错误首先出现，并且在执行宏时我看不到选项Step by step设计视图。



如果我添加一个新的autoexec宏（重命名以前存在的），当它尝试调用它上面的第一个函数时它会再次失败，（另一个函数）名称）以类似的模式。



我找到了函数的使用。它们位于代码模块中。

Hello Everybody: As I mentioned in my previous question, I´m working with an Access application and I´m getting an error message when I load the database.

The error number is 2950. It occurs when the macro Autoexec runs, and it tries to execute the code of a function (the first one in it).

I suppose (I never worked before with this platform) I could debug the flow of execution of the code of the function involved, following it step by step, as I normally does in Visual Basic or Excel, but I just can´t here. I think viewing the code internally maybe I could see the reason why autoexec fails and I can´t run the app from the source code. I guess I have an installation issue, but I need to see where it´s breaking and why.

Is it posible to follow step by step the flow of execution of an Access application starting at the autoexec macro ?

What I have tried:

I set a breakpoint in the first executable line of code in the first involved function, but the flow never gets to that point, the error occurs first, and I cannot see the option "Step by step" when executing the macro at the design view.

If I add a new autoexec macro (renaming the previously existent), it fails again when tries to call the first function on it, (another function name) in a similar pattern.

I have located the ubication of the functions. They´re in code modules.

推荐答案

用于Access数据库VBA 2950的快速Google提供了这种可能性 [ ^ ]。

A quick Google for "Access database VBA 2950" comes up with this possibility[^].

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