这个C代码有什么问题？ [英] What is wrong with this C code ?

问题描述

我使用过幂声明。但它不能正常工作，因为每当我输入（编译后）5提升到2，它应该是数学上的25。但它显示24.为什么会这样？它做得很好，当我做2提升到3 = 8 .....



我尝试过：

I have used power statement. But it is not working fine because whenever I type (after compilation)that 5 raised to power 2, It should be 25 mathematically. But it is showing 24. Why is it so? It works fine when I did 2 raised to power 3=8.....

What I have tried:

#include <stdio.h>
#include <math.h>
int main ()
{
    int a,b;
    printf ("Enter any value.\n");
    scanf ("%d",&a);
    printf ("Enter the number to which it should be raised.\n");
    scanf ("%d",&b);
    int num;
    num=pow(a,b);
    printf ("The result is %d",num);
    return 0;
}

推荐答案

pow（）返回 double ，从这里开始： C库函数pow（） [ ^ ]

pow() returns double, start here : C library function pow()[^]

正如Mehdi所说已经告诉过你：你已经将 num 声明为 int 类型，但它应该是 double 。如有疑问，请使用Google查找 pow（）函数的文档。

As Mehdi has already told you: You have declared num as int type, but it should be double. If in doubt use Google to find the documentation for the pow() function.

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