解决*和*拒绝Bluebird中的所有承诺 [英] Resolve *and* reject all promises in Bluebird

问题描述

我正在寻找从promise数组获得解析和拒绝的方法。我目前依赖Bluebird实现，因此ES6兼容解决方案也适用。

I'm looking for the way to get both resolutions and rejections from promise array. I'm currently counting on Bluebird implementation, so ES6 compatible solution would be suitable, too.

最让人想到的是使用Bluebird的 Promise.settle 为此，我认为承诺检查是不必要的复杂问题：

The best thing that comes to mind is to use Bluebird's Promise.settle for that, and I consider promise inspections an unnecessary complication here:

  let promises = [
    Promise.resolve('resolved'),
    Promise.resolve('resolved'),
    Promise.reject('rejected')
  ];

  // is there an existing way to do this?
  let resolvedAndRejected = Promise.settle(promises)
  .then((inspections) => {
    let resolved = [];
    let rejected = [];

    inspections.forEach((inspection) => {
      if (inspection.isFulfilled())
        resolved.push(inspection.value());
      else if (inspection.isRejected())
        rejected.push(inspection.reason());
    });

    return [resolved, rejected];
  });

  resolvedAndRejected.spread((resolved, rejected) => {
    console.log(...resolved);
    console.error(...rejected);
  });

对于100％履约率不是一种选择或者不是一种选择的情况，这看起来很简单目标，但我甚至不知道配方的名称。

It looks like a trivial task for the cases where 100% fulfillment rate isn't an option or a goal, but I don't even know the name for the recipe.

在Bluebird或其他承诺实施中是否有一种简洁且经过充分验证的方法来处理-in运算符或扩展名？

Is there a neat and well-proven way to handle this in Bluebird or other promise implementations - built-in operator or extension?

推荐答案

自OP询问后，添加了完整性的答案。以下是我要做的事情：

Added answer for completeness since OP asked. Here is what I'd do:

 const res = Promise.all(promises.map(p => p.reflect())) // get promises
   .then(values => [
          values.filter(x => x.isFulfilled()).map(x => x.value()), // resolved
          values.filter(x => x.isRejected()).map(x => x.reason()) // rejected
   ]);

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