我使用适当的代码在netbeans中制作计算器“a + b + c ...”但它没有做多次操作“a + b-c ......”在时间 [英] I made calculator in netbeans with proper code it do "a+b+c..." but it failed to do multiple operation "a+b-c..." at time

问题描述

我使用正确的代码在netbeans中制作了计算器a + b + c ......但是它没有按时执行多次操作a + bc ......



如何插入支架来解决这个问题



我尝试了什么：



我的代码是

1.多次打印数字

I made calculator in netbeans with proper code it do "a+b+c..." but it failed to do multiple operation "a+b-c..." at time

How to insert Bracket to solve this problem

What I have tried:

my code is
1. Printing a number multiple time

if(s==null)
        {
            jTextField.setText(jTextField.getText()+"1");
        }
        else
        {
            //totle+=Double.parseDouble(jTextField1.getText());
           p=s;
            s=null;
            jTextField.setText("1");
        }

//here double totle=0; string s=sign; p=for identifying sign;

2. Code for add.
        s="+";
        totle+=Double.parseDouble(jTextField.getText());

//3. code for subtract.

         s="-";
        if(totle!=0){
        totle-=Double.parseDouble(jTextField.getText());}
        else
        {
            totle=Double.parseDouble(jTextField.getText());
        }
         
//4. code for equal to sign

         if(p=="+")   
        {
        totle+=Double.parseDouble(jTextField.getText());
        
        jTextField.setText(""+totle);
        
        totle-=totle;
        s=null;
        }
        else if(p=="-")
       {
           
         totle-=Double.parseDouble(jTextField.getText());
        
        jTextField.setText(""+totle);
        totle-=totle;
        s=null;  .

推荐答案

我无法弄清楚你的代码，因为它似乎有点随机，尽管有很多缺失。你应该在开始编码之前首先尝试写出纸上所需的步骤，所以它应该是这样的：

I cannot quite figure out your code as it seems somewhat random, although there is quite a lot missing. You should try writing out the steps required on paper first before you start coding, so it should be something like:

SET Total = 0
do
{
    get next input value
    get next operator
    switch (operator)
    {
    case '+'
        add value to Total
        break
    case '-'
        subtract value from Total
        break
//  etc for other operators
    }
    display Total
} while (operator != '=')

在等于运算符处理后输入新值时，可以添加更多逻辑来重置Total。

You can add further logic to reset Total when a new value is entered after the equals operator has ben handled.

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