选择随机< li>元件 [英] Select random <li> element
本文介绍了选择随机< li>元件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试为我的HTML 5播放器制作一个随机播放按钮。我的播放器设置如下,以便进入下一首曲目:
I'm trying to make a shuffle button for my HTML 5 player. My player is set up like this to go the next track:
$('.nextbutton').on("click", function(){
var next = $('li.playing').next();
if (!next.length) next = $('#stuff ul li').first();
next.addClass('playing').siblings().removeClass('playing');
var title = $('a#tunes img', next).attr("title");
$("a.songtitle span").text(title);
var artist = $('a#tunes img', next).attr("artist");
$("a.songartist span").text(artist);
audio.load($('a#tunes', next).attr('data-src'));
audio.play();
});
此代码可用于转到下一首歌曲,但如何更改此代码以使其选择随机< li>
元素而不是 .next();
< li> ;
?感谢您的时间和考虑。希望你能帮助我!
This code works to go to the next song but how can I change this to make it so it selects a random <li>
element instead of the .next();
<li>
? Thanks for your time and consideration. Hope you can help me!
推荐答案
var next = Math.floor(Math.random() * jQuery('#stuff ul li').length + 1));
var nextLi = jQuery('#stuff ul li').get(next);
它将获得0到 li $之间的随机数c $ c> s然后得到
li
。
It'll get random number between 0 and count of li
s and then get this li
.
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