这是如何工作的..函数调用.. [英] How this works..in function call..

问题描述

main( )
{
int x, y, s = 2 ;
s *= 3 ;
y = f ( s ) ;
x = g ( s ) ;
printf ( "\n%d %d %d", s, y, x ) ;
}
int t = 8 ;
f ( int a )
{
a += -5 ;
t -= 4 ;
return ( a + t ) ;
}
g ( int a )
{
a = 1 ;
t += a ;
return ( a + t ) ;
}

我的尝试：



s和y的值可以理解，但x是怎么来的，



ans s，y，x = 6,5,6

What I have tried:

value of s and y understood but how this x came ,,

ans s,y,x=6,5,6

推荐答案

当你不理解你的代码在做什么或为什么它做它的作用时，答案是调试器。

使用调试器查看代码正在执行的操作。只需设置断点并查看代码执行情况，调试器允许您逐行执行第1行并在执行时检查变量，这是一个令人难以置信的学习工具。



调试器 - 维基百科，免费的百科全书 [ ^ ]

掌握Visual Studio 2010中的调试 - 初学者指南 [ ^ ]

使用Visual Studio 2010进行基本调试 - YouTube [ ^ ]

调试器在这里向您展示您的代码正在做什么以及您的任务是与它应该做的比较。

调试器中没有魔法，它没有发现错误，它只是帮助你。当代码没有达到预期的效果时，你就会接近一个错误。

When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute, it is an incredible learning tool.

Debugger - Wikipedia, the free encyclopedia[^]
Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]
Basic Debugging with Visual Studio 2010 - YouTube[^]
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.

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