为什么程序的输出是3323321？返回函数在函数abc中做了什么？ [英] Why the output of the program is 3323321? What does return function does in function abc?

问题描述

#include<stdio.h>
void abc(char*s)
{

if(s[0]=='\0')
    return;
abc(s+1);
abc(s+1);
printf("%c",s[0]);
}
int main()
{
    abc("123");
}

我的尝试：



i已尝试递归执行函数abc（char * s）。

What I have tried:

i have tried recursions for the execution of function abc(char *s).

推荐答案

引用：

为什么程序的输出是3323321？函数abc中返回函数的作用是什么？

Why the output of the program is 3323321? What does return function does in function abc?

这就是你要求的。



当你不明白您的代码正在做什么或为什么它做它的作用，答案是调试器。

使用调试器来查看代码正在做什么。只需设置断点并查看代码执行情况，调试器允许您逐行执行第1行并在执行时检查变量，这是一个令人难以置信的学习工具。



调试器 - 维基百科，免费的百科全书 [ ^ ]

掌握Visual Studio 2010中的调试 - 初学者指南 [ ^ ]

使用Visual Studio 2010进行基本调试 - YouTube [ ^ ]



调试器在这里向您展示您的代码在做什么你的任务是与它应该做的事情进行比较。

调试器中没有魔法，它没有发现错误，它只是帮助你。当代码没有达到预期的效果时，你就会接近一个错误。

That is what you asked for.

When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute, it is an incredible learning tool.

Debugger - Wikipedia, the free encyclopedia[^]
Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]
Basic Debugging with Visual Studio 2010 - YouTube[^]

The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.

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