你能算出编码错误吗？ [英] Can u figure out the coding error ?
问题描述
＃包括< stdio.h中>
int main（无效）
{
float dis;
浮动费用，od，odPay;
char车辆;
printf（插入车辆（V / C / T）：）;
scanf（％c，& vehicle）;
printf（插入你走过的距离：）;
scanf（％f，& dis）;
if（vehicle =='V'）
if（dis< = 50）
cost = 45.50 * dis;
printf（旅行费用为％.2f \ n，费用）;
else
od = dis - 50;
odPay = od * 45.00;
cost =（45.50 * 50）+ odPay;
printf（旅行费用为％.2f \ n，费用）;
else if（vehicle =='C'）
if（dis< = 50）
cost = 55.00 * dis;
printf（旅行费用为％.2f \ n，费用）;
else
od = dis - 50;
odPay = od * 56.50;
cost =（55.00 * 50）+ odPay;
printf（旅行费用为％.2f \ n，费用）;
else if（vehicle =='T'）
if（dis< = 50）
cost = 50.50 * dis;
printf（旅行费用为％.2f \ n，费用）;
else
od = dis - 50;
odPay = od * 50.00;
cost =（50.50 * 50）+ odPay;
printf（旅行费用为％.2f \ n，费用）;
我的尝试：
这是编译时显示的错误
vehicle.c：在函数'main'中：
vehicle.c：20：3：错误：'其他'没有先前'如果'
其他
^ ~~~
车辆.c：25：2：错误：'else'没有先前'if'
否则if（vehicle =='C'）
^ ~~~
vehicle.c：29：17：错误：'其他'没有先前'如果'
其他
^ ~~~
vehicle.c：34：4：错误：'else'没有先前'if'
否则if（vehicle =='T'）
^ ~~~
vehicle.c：38：3：错误：'else'没有先前'if'
else
是。你能吗？
这很明显，你重复同样的错误次数。
格式为如果声明是：
if （条件）
语句其中
语句可以是单个语句：
if （条件）
DoSomethingSimple;或复合语句：
如果（条件）
{
DoSomethingSimple;
DoSomethingElseSimple;
}
所以当你这样写：
if （vehicle == ' V'）
if （dis< = 50 ）
cost = 45 。 50 * dis;
printf（ 旅行费用是％.2f \ n，费用）;
else编译器无法理解你想要做什么。
如果我缩进它，它更明显：
如果（vehicle == ' V'）
if （dis< = < span class =code-digit> 50 ） // 这是前一个if的简单陈述
cost = 45 。 50 * dis; // 这是第二个if
printf（ 旅行费用是％.2f \ n，费用）; // 这不在ifs
else // 这与此无关。
总是使用复合语句，特别是在你开始时 - 它使它更清晰，更容易修改。
if （vehicle == ' V'）
{
if （dis< = 50 ）
{
cost = 45 。 50 * dis;
printf（ 旅行费用是％.2f \ n，费用）;
}
else
{
...并缩进代码！
问题是你没有在条件表达式中包含多语句子句的大括号。
换句话说 - 你应该使用这种格式：
if （表达式）
{
// 陈述......（一个或多个，无所谓）
}
else if （anotherExpression）
{
// 陈述......（一个或多个，无所谓）
}
else
{
// 陈述......（一个或多个，无所谓）
}
//我想我的抽奖速度较慢。
你需要学习大括号的用法{}在C / C ++ / C＃源代码中。然后你会明白是什么问题。
这是你在C 101班的第一天学到的东西。检查你的笔记。
#include<stdio.h>
int main(void)
{
float dis;
float cost, od, odPay;
char vehicle;
printf("Insert ur vehicle ( V / C / T ) : ");
scanf("%c", &vehicle);
printf("Insert distance that u travelled : ");
scanf("%f", &dis);
if (vehicle == 'V')
if (dis <= 50)
cost = 45.50 * dis;
printf("Charge for travel is %.2f \n", cost);
else
od = dis - 50;
odPay = od * 45.00 ;
cost =( 45.50 * 50 ) + odPay;
printf("Charge for travel is %.2f \n", cost);
else if (vehicle == 'C')
if (dis <= 50)
cost = 55.00 * dis;
printf("Charge for travel is %.2f \n", cost);
else
od = dis - 50;
odPay = od * 56.50 ;
cost =( 55.00 * 50 ) + odPay;
printf("Charge for travel is %.2f \n", cost);
else if (vehicle == 'T')
if (dis <= 50)
cost = 50.50 * dis;
printf("Charge for travel is %.2f\n", cost);
else
od = dis - 50;
odPay = od * 50.00 ;
cost =( 50.50 * 50 ) + odPay;
printf("Charge for travel is %.2f \n", cost);
What I have tried:
This is the error which is showing when compiling
vehicle.c: In function ‘main’:
vehicle.c:20:3: error: ‘else’ without a previous ‘if’
else
^~~~
vehicle.c:25:2: error: ‘else’ without a previous ‘if’
else if (vehicle == 'C')
^~~~
vehicle.c:29:17: error: ‘else’ without a previous ‘if’
else
^~~~
vehicle.c:34:4: error: ‘else’ without a previous ‘if’
else if (vehicle == 'T')
^~~~
vehicle.c:38:3: error: ‘else’ without a previous ‘if’
else
Yes. Can you?
It's pretty obvious, and you are repeating the same mistake loads of times.
The format of anifstatement is:
if(condition) statementWhere
statementcan be a single statement:
if (condition) DoSomethingSimple;or a Compound statement:
if (condition) { DoSomethingSimple; DoSomethingElseSimple; }
So when you write this:
if (vehicle == 'V') if (dis <= 50) cost = 45.50 * dis; printf("Charge for travel is %.2f \n", cost); elsethe compiler can't understand what you are trying to do.
If I indent it, it's a lot more obvious:
if (vehicle == 'V') if (dis <= 50) // This is a simple statement for the previous if cost = 45.50 * dis; // This is a simple statement for the second if printf("Charge for travel is %.2f \n", cost); // This is outside both ifs else // This has nothing to match with.
Always use compound statements, especially when you are starting out - it makes it a lot clearer and easier to modify.
if (vehicle == 'V') { if (dis <= 50) { cost = 45.50 * dis; printf("Charge for travel is %.2f \n", cost); } else { ...And indent your code!
The problem is you have not included braces for multi-statement clauses in your conditional expressions.
In other words - you should use this type of format :
if( expression ) { // statements ... (one or many, doesn't matter) } else if( anotherExpression ) { // statements ... (one or many, doesn't matter) } else { // statements ... (one or many, doesn't matter) }
// I guess I was slower on the draw.
You need to learn the usage of braces{}in C/C++/C# source code. Then you will understand what is the problem.
This is something you learn on first day of C 101 classes. Check you notes.
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