请解释为什么这段代码不起作用.. [英] Pls explain why this code is not going to work..

问题描述

％f不是double的格式说明符吗？我已经看过几次了......请解释........................



我尝试过：

Is %f not a format specifier for double? I have seen a couple of times that it is..please Explain........................

What I have tried:

#include<stdio.h>
#include<conio.h>
void main()
{
   double d;
   scanf("%f",&d);
   printf("%f",d);
   getch();

}

推荐答案

％f是float的格式代码，而不是double。由于double是浮点数的两倍，当你将浮点值读入内存中时，你获得的值是不正确的。

请尝试％lf。

%f is the format code for a float, not a double. Since a double is twice the size of a float, when you read a float value into the memory for a double, the value you get is not correct.
Try %lf instead.

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