我收到一条评论“id返回1退出状态。我做错了什么 [英] I am getting an comment "id returned 1 exit status. What have I done wrong
本文介绍了我收到一条评论“id返回1退出状态。我做错了什么的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
#include< stdio.h>
#include< stdlib.h> //记得如果你打算使用exit（），你需要
//这个头文件
main（）
{
//尽管是一个很长的程序，你只需要两个变量：
//第一个菜单一个，第二个菜单一个
int choice1;
int choice2;
//潜在的十年选择
printf（你想看到什么？\ n）;
printf（1. 1980年代\ n）;
printf（2. 1990年代\ n）;
printf（3。2000年代\ n）;
printf（4.Quit\\\
）;
//顶部菜单选项和使
//得到
//信息的switch语句包含在
/的do-while循环中/确保四个菜单选项中的一个
//
do
{
printf（输入您的选择：）;
scanf（％d，& choice1）;
开关（choice1）
{
//在第一种情况下，用户选择了1980年代。现在它是
//时间来查看他们需要什么具体信息。
case（1）：
{
printf（\ n你想看到什么？\ n）;
printf（1。Baseball \ n）;
printf（2.the movies\）;
printf（3.美国总统）;
printf（4.Quit\\\
）;
printf（输入您的选择：）;
scanf（％d，& choice2）;
if（choice2 == 1）
{
printf（\ n \\\
nWorld Series Chapions）;
printf（1980年代：\ n）;
printf（1980：Philadelphia Phillies\\\
）;
printf（1981：Los Angeles Dodgers \ n）;
printf（1982：St. Louis Cardinals\\\
）;
printf（1983：Baltimore Orioels \ n）;
printf（1984：Detroit Tigers \ n）;
printf（1985：Kansas City Royals \ n）;
printf（1986：New York Mets \ n）;
printf（1987：Minnesota Twins \ n）;
printf（1988：Los Angeles Dodgers \ n）;
printf（1989 Oakland A's \ n）;
printf（\ n \ nn \ n）;
休息;
}否则if（choice2 == 2）
{
printf（1980年代的\ n \ nnOscar赢得电影：\ n）;
printf（1980：Ordinary People\\\
）;
printf（1981：Chariots of Fire \ n）;
printf（1982：Ghandi \ n）;
printf（1983：Endearment的条款）;
printf（1984：Amadeus \ n）;
printf（1985：Out of Africa\\\
）;
printf（1986：Platoon \ n）;
printf（1987：The Last Emperor \ n）;
printf（1988：Rain man \ n）;
printf（1989：驾驶Miss Daisy）;
printf（\ n \ nn \ n）;
休息;
}否则if（choice2 == 3）
{
printf（1980年代的美国总统：\ n）;
printf（1980：Jimmy Carter \ n）;
printf（1981-1988：Ronald Reagen \ n）;
printf（1989：George Bush \ n）;
printf（\ n \ nn \ n）;
休息;
}否则if（choice2 == 4）
{
exit（1）;
}其他
{
printf（抱歉，这不是一个有效的选择！\ n）;
休息;
}
}
//这是1990年代的情况。
//与顶层菜单不同，没有数据验证
// do-while循环
case（2）：
{
printf（\ n \ n你想看到什么？\ n）;
printf（1。Baseball \ n）;
printf（2.the movies\）;
printf（3。美国Presidients \ n）;
printf（4.Quit\\\
）;
printf（输入你的选择：）;
scanf（％d，& choice2）;
if（choice2 == 1）
{
printf（\ n \ n世界系列赛冠军）;
printf（1990年代：\ n）;
printf（1990：Cincinatti reds\\\
）;
printf（1991：Minnesota Twins \ n）;
printf（1992：Toronto Blue jays\\\
）;
Printf（1993：Toronto Blue Jays \ n）;
printf（1994：No World Series \ n）;
printf（1995：Atlanta Braves \ n）;
printf（1996：New York Yankees \ n）;
printf（1997：Florida Marlins \ n）;
printf（1998：New York Yankees \ n）;
printf（1999 New York Yankess \ n）;
printf（\ n \ nn \ n）;
休息;
}否则如果（choice2 == 2）
{
printf（\ n \ n，奥斯卡获奖电影）;
printf（1990年代：\ n）;
printf（1990：与狼共舞）;
printf（1991：The Silence of the Lambs \ n）;
printf（1992：Unforgiven \ n）;
printf（1993：Schindlers List \\\
）;
printf（1994：？\ n）;
printf（1995：?? \ n）;
printf（1996：The English Patient \ n）;
printf（1997：Titanic \ n）;
printf（1998：Shakespere in Love\ n）;
printf（1999：American Beauty \ n）;
printf（\ n \ nn \ n）;
休息;
}否则if（choice2 == 3）
{
printf（1990年代的\ n \ nnUS总统：\ n）;
printf（1990-1992：George Bush \ n）;
printf（1993-1999：Bill Clinton \ n）;
printf（\ n \ nn \ n）;
休息;
}否则if（choice2 == 4）
{
exit（1）;
}其他
{
printf（抱歉，这不是一个有效的选择！\ n）;
休息;
}
}
//用户选择2000年
案例的部分（3）：
{
printf（你想看到什么？\ n）;
printf（1。Baseball \ n）;
printf（2.The Movies \ n）;
printf（3.美国总统）;
printf（4.Quit\\\
）;
printf（输入您的选择：）;
scanf（％d，& choice2）;
if（choice2 == 1）
{
printf（\ n \ nnWorld series Champions of）;
printf（The 2000's：\ n）;
printf（2000：New York Yankees \ n）;
printf（2001：Arizona Diamondbacks \ n）;
printf（2002：Anaheim Angels \ n）;
printf（2003：Florida Marlins \ n）;
printf（2004：Boston Red Sox \ n）;
printf（2005：Chicago White Sox）;
printf（2006：St. Louis Cardinals\\\
）;
printf（2007：Boston Red Sox \ n）;
printf（2008：Philadelphia Phillies\\\
）;
printf（2009：New York Yankees \ n）;
printf（\ n \ nn \ n）;
休息;
}否则如果（choice2 == 2）
{
printf（\ n \ nnOscar赢得电影）;
printf（2000年代：\ n）;
printf（2000：Gladiator\\\
）;
printf（2001：A Beautiful Mind \ n）;
printf（2002：Chicago \ n）;
printf（2003：指环王之家）;
printf（2004：Million Dollar Baby \ n）;
printf（2005：Crash \ n）;
printf（2006：The Deeded\\\
）;
printf（2007：没有老人的国家）;
printf（2008：Slumdog Millionaire \ n）;
printf（2009：The Hurt Locker \ n）;
printf（\ n \ nn \ n）;
休息;
}否则if（choice2 == 3）
{
printf（\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n'中的总统）;
printf（2000：Bill Clinton \ n）;
printf（2001-2008：George W Bush \ n）;
printf（2009：Barack Obama \ n）;
printf（\ n \ nn \ n）;
休息;
}否则if（choice2 == 4）
{
exit（1）;
}其他
{
printf（抱歉，这不是一个有效的选择！\ n）;
休息;
}
}
case（4）：
exit（1）;
默认值：printf（\ n％d不是有效的选择。\ n）;
printf（再试一次。\ n）;
休息;
}
} while（（choice1< 1）||（choice1> 4））;
返回0;
}
我的尝试：
我试过查看程序并且没有明显的事情发生。
解决方案
当你不明白你的代码在做什么或为什么它完成了它的工作，答案是调试器。
使用调试器查看你的代码在做什么。只需设置断点并查看代码执行情况，调试器允许您逐行执行第1行并在执行时检查变量，这是一个令人难以置信的学习工具。
调试器 - 维基百科，免费的百科全书 [ ^ ]
掌握Visual Studio 2010中的调试 - 初学者指南 [ ^ ]
调试器在这里显示你的代码正在做什么，你的任务是与它应该做什么进行比较。
调试器中没有魔法，它没有发现错误，它只是帮助你。当代码没有达到预期的效果时，你就接近了一个错误。
你是否设置了断点以捕获代码流？调试器可以帮助你大大节省你的时间。
我可以看到需要修复的错误：默认：printf（ \ n％d不是有效选择。 \ n）;应为：
默认：printf（ \ n％d不是有效的选择。\ n，choice1）;
#include <stdio.h>
#include <stdlib.h> // remember if you plan to use exit(), you need
// this header file
main()
{
// Despite being a long program, you only need two variables:
// one for the first menu and one for the second menu
int choice1;
int choice2;
// The potential decade choices
printf("What do you want to see?\n");
printf("1. The 1980's\n");
printf("2. the 1990's\n");
printf("3. The 2000's\n");
printf("4. Quit\n");
//The top menu choice and the switch statement that makes the
// resulting
//information appear are encased in a do-while loop that
//ensures one
// of the four menu choices are made
do
{
printf("Enter your choice: ");
scanf(" %d", &choice1);
switch (choice1)
{
//In the first case, the user picked the 1980's. Now it
//time to see what specific info they need.
case (1) :
{
printf("\nWhat would you like to see?\n");
printf("1. Baseball\n");
printf("2. The movies\n");
printf("3. US Presidents\n");
printf("4. Quit\n");
printf("Enter your choice: ");
scanf(" %d", &choice2);
if (choice2 ==1)
{
printf("\n\nWorld Series Chapions ");
printf(" of the 1980's:\n");
printf("1980: Philadelphia Phillies\n");
printf("1981: Los Angeles Dodgers\n");
printf("1982: St. Louis Cardinals\n");
printf("1983: Baltimore Orioels\n");
printf("1984: Detroit Tigers\n");
printf("1985: Kansas City Royals\n");
printf("1986: New York Mets\n");
printf("1987: Minnesota Twins\n");
printf("1988: Los Angeles Dodgers\n");
printf(" 1989 Oakland A's\n");
printf("\n\n\n");
break;
} else if (choice2 == 2)
{
printf("\n\nOscar winning movies in the 1980's:\n");
printf("1980: Ordinary People\n");
printf("1981: Chariots of Fire\n");
printf("1982: Ghandi\n");
printf("1983: Terms of Endearment\n");
printf("1984: Amadeus\n");
printf("1985: Out of Africa\n");
printf("1986: Platoon\n");
printf("1987: The Last Emperor\n");
printf("1988: Rain man\n");
printf("1989: Driving Miss Daisy");
printf("\n\n\n");
break;
} else if (choice2 == 3)
{
printf("\n\n US Presidents in the 1980's:\n");
printf("1980: Jimmy Carter\n");
printf(" 1981-1988: Ronald Reagen\n");
printf("1989: George Bush\n");
printf("\n\n\n");
break;
} else if (choice2 == 4)
{
exit(1);
} else
{
printf("Sorry, that is not a valid choice!\n");
break;
}
}
//This is the case for the 1990's.
// Unlike the top menu, there isn't a data validation
//do-while loop
case (2) :
{
printf("\n\n What would you like to see?\n");
printf("1. Baseball\n");
printf("2. The movies\n");
printf("3. US Presidients\n");
printf("4. Quit\n");
printf(" Enter you choice:");
scanf(" %d", &choice2);
if (choice2 ==1)
{
printf("\n\n World Series Champions of");
printf("the 1990's:\n");
printf("1990: Cincinatti reds\n");
printf("1991: Minnesota Twins\n");
printf("1992: Toronto Blue jays\n");
Printf("1993: Toronto Blue Jays\n");
printf("1994: No World Series\n");
printf("1995: Atlanta Braves\n");
printf("1996: New York Yankees\n");
printf("1997: Florida Marlins\n");
printf("1998: New York Yankees\n");
printf("1999 New York Yankess\n");
printf("\n\n\n");
break;
} else if (choice2 == 2)
{
printf("\n\n Oscar winning Movies in ");
printf(" the 1990's:\n");
printf("1990: Dances with Wolves\n");
printf("1991: The Silence of the Lambs\n");
printf("1992: Unforgiven\n");
printf("1993: Schindlers List\n");
printf("1994: ?\n");
printf("1995: ??\n");
printf("1996: The English Patient\n");
printf("1997: Titanic\n");
printf("1998: Shakespere in Love\n");
printf("1999: American Beauty\n");
printf("\n\n\n");
break;
} else if (choice2 == 3)
{
printf("\n\nUS Presidents in the 1990's:\n");
printf("1990-1992: George Bush\n");
printf("1993-1999: Bill Clinton\n");
printf("\n\n\n");
break;
} else if (choice2 == 4)
{
exit (1);
} else
{
printf("Sorry, that is not a valid choice!\n");
break;
}
}
// The section for when the user selects the 2000's
case (3) :
{
printf("\n\nWhat would you like to see?\n");
printf("1. Baseball\n");
printf("2. The Movies\n");
printf("3. US Presidents\n");
printf("4. Quit\n");
printf("Enter your choice:");
scanf(" %d", &choice2);
if (choice2 == 1)
{
printf("\n\nWorld series Champions of ");
printf("The 2000's:\n");
printf("2000: New York Yankees\n");
printf("2001: Arizona Diamondbacks\n");
printf("2002: Anaheim Angels\n");
printf("2003: Florida Marlins\n");
printf("2004: Boston Red Sox\n");
printf("2005: Chicago White Sox");
printf("2006: St. Louis Cardinals\n");
printf("2007: Boston Red Sox\n");
printf("2008: Philadelphia Phillies\n");
printf("2009: New York Yankees\n");
printf("\n\n\n");
break;
} else if (choice2 == 2)
{
printf("\n\nOscar winning movies in ");
printf("the 2000's: \n");
printf("2000: Gladiator\n");
printf("2001: A Beautiful Mind\n");
printf("2002: Chicago\n");
printf("2003: The Lord of the Rings\n");
printf("2004: Million Dollar Baby\n");
printf("2005: Crash\n");
printf("2006: The Departed\n");
printf("2007: No Country for Old Men\n");
printf("2008: Slumdog Millionaire\n");
printf("2009: The Hurt Locker\n");
printf("\n\n\n");
break;
} else if (choice2 == 3)
{
printf("\n\nUS Presidents in the 2000's\n");
printf("2000: Bill Clinton\n");
printf("2001-2008: George W Bush\n");
printf("2009: Barack Obama\n");
printf("\n\n\n");
break;
} else if (choice2 == 4)
{
exit(1);
} else
{
printf("Sorry, that is not a valid choice!\n");
break;
}
}
case (4) :
exit (1);
default : printf("\n%d is not a valid choice.\n");
printf("Try again.\n");
break;
}
} while ((choice1 < 1) || (choice1 > 4));
return 0;
}
What I have tried:
I have tried looking over the program and nothing obvious his coming up.
解决方案
When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute, it is an incredible learning tool.
Debugger - Wikipedia, the free encyclopedia[^]
Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.
Have you set breakpoints to catch the flow of your code? The debugger can help you greatly and save you heaps of time.
I can see an error that need fixing:default : printf("\n%d is not a valid choice.\n");should be:
default : printf("\n%d is not a valid choice.\n", choice1);
这篇关于我收到一条评论“id返回1退出状态。我做错了什么的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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