嘿伙计们，有人能告诉我如何解决这个问题吗？ [英] Hey guys, can someone tell me how to fix this problem?

问题描述

#include<stdio.h>
#include<conio.h>

void main()  
{
    int i = 0;
    char ch;
    clrscr();

    for (i = 0; i < 256; i++)
    {
        printf("%c ",ch)<-- function call missing (
        ch = ch + 1;
    }<-- Statement missing ;

    getch();
}

我尝试了什么：



好​​吧，在学校我还没有IT课，所以我真的不知道该怎么做所以我认为你可以帮忙，谢谢

What I have tried:

Well,at school i do not have IT class yet,so i really don't know what to do so i thought you could help,thanks

推荐答案

根据NotPolitcallyCorrect - Professional Profile [ ^ ]和 PIEBALDconsult - 专业档案 [ ^ ]以下应该是解决方案：

According to the comments of NotPolitcallyCorrect - Professional Profile[^] and PIEBALDconsult - Professional Profile[^] the following should be the solution:

#include<stdio.h>
#include<conio.h>

void main()  
{
    int i = 0;
    char ch;
    clrscr();

    for (i = 0; i < 256; i++)
    {
        printf("%c ",ch); // The missing semicolon
        ch = ch + 1;
    }

    getch();
}

请记住，我不是给出解决方案的人，上面提到的两个成员就是那些，我最后才把它写下来;）

Keep in mind I was _not_ the one giving the solution, the two members mentioned above are the ones, I only wrote it down finally ;)

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