如何在标签中显示文本框的所有值 [英] How to display all values of text box in label

问题描述

当我选择它时我可以显示一个项目

但是我不能一次显示所有项目。



我尝试了什么：



i试过这个

form1

  private   void  btn_voit_Click（ object  sender，EventArgs e）
 {
  string  textboxchoix = listBox2.Text; 
 Form2 frm =  new  Form2（textboxchoix）; 
 frm.Show（）; 
} 

form2

  public  Form2（ string  textboxchoix）
 {
 InitializeComponent（）; 
 label_choix.Text = textboxchoix; 
 
} 

解决方案

向Form2添加方法

  public   void  AddString（ string  s）
 {
 lable_choix.Text + = s; 
} 

并为每个额外项目调用。

引用：

我知道如何在标签中显示文本框但如果我选择它将显示它只显示一个项目为exmaple我有10个元素n我的文本框但是当我显示它只显示一个我希望显示所有元素

这不是TextBox - 它是一个ListBox。

试试这个：

 StringBuilder sb = new StringBuilder（）; 
 foreach（listBox1.Items中的对象x）
 {
 sb.AppendLine（x.ToString（））; 
} 
 Form2 frm = new Form2（sb.ToString（））; 
 frm.Show（）; 

已修改，



如果我理解正确，你试图将项目从表单上的列表框移动到另一个表单上的另一个列表框。



如果这是正确的，那么你需要定义一个公共方法在接收表格上并传递要添加到方法中的项目。



在发送方面，您收集项目并调用方法。但请注意，您需要知道表单的实例，仅仅知道该类是不够的



请考虑以下示例



在接收表格中定义如下方法

  public   bool  AddListboxItems（ string  [] items）{
 此 .listBox1.Items.AddRange（项目）; 
 
  return   true ; 
} 
 

请记住使用正确的列表框名称



如果接收表单的类是例如Form1，然后以下应该将项目发送到类的新实例

 ListBox lb1 =  new  ListBox（）; 
 
 lb1.Items.Add（  first）; 
 lb1.Items.Add（  second）; 
 lb1.Items.Add（  third）; 
 
  //  选择项目0和2  
 lb1.SelectionMode = SelectionMode.MultiSimple; 
 lb1.SelectedItems.Add（lb1.Items [ 0 ]）; 
 lb1.SelectedItems.Add（lb1.Items [ 2 ]）; 
 
 Form1 frm1 =  new  Form1（）;  //  接收实例应以另一种方式计算 
 
  string  [] items =  new   string  [lb1。 SelectedItems.Count]; 
 
  for （ int  counter =  0 ; counter <  lb1.SelectedItems.Count; counter ++）{
 items [counter] = lb1.SelectedItems [counter] .ToString （）; 
} 
 
 frm1.AddListboxItems（items）; 
 

请注意，接收表单是在代码中创建的，因此在实际情况下，您可能需要引用已存在的表单。

i can display one item when i select it
but i can't display all items at once.

What I have tried:

i tried this
form1

private void btn_voit_Click(object sender, EventArgs e)
        {
            string textboxchoix = listBox2.Text;           
            Form2 frm = new Form2(textboxchoix);
            frm.Show();
        }

form2

public Form2(string textboxchoix)
        {
            InitializeComponent();
           label_choix.Text = textboxchoix;
            
        }

解决方案

Add a method to Form2

public void AddString(string s)
   {
   lable_choix.Text += s;
   }

And call that for each additional item.

Quote:

i know how to display textbox in label but if i select it will display and it only display one item for exmaple i have 10 element n my textbox but when i display it it shows only one i want display all element

That';s not a TextBox - it's a ListBox.
Try this:

StringBuilder sb = new StringBuilder();
foreach (object x in listBox1.Items)
    {
    sb.AppendLine(x.ToString());
    }
Form2 frm = new Form2(sb.ToString());
frm.Show();

Modified,

If I understand correctly, you're trying to move items from a listbox on a form to another listbox on a different form.

If that is correct then you need to define a public method on the receiving form and pass the items to be added to the method.

On the "sending" side you gather the items and call the method. However note that you need to know the instance for the form, it's not sufficient to only know the class

Consider the following example

On the "receiving" form define a method like the following

public bool AddListboxItems(string[] items) {
   this.listBox1.Items.AddRange(items);

   return true;
}

Remember to use the correct list box name

And if the class of the receiving form is for example Form1 then the following should send the items to a new instance for the class

ListBox lb1 = new ListBox();

lb1.Items.Add("first");
lb1.Items.Add("second");
lb1.Items.Add("third");

// select items 0 and 2
lb1.SelectionMode = SelectionMode.MultiSimple;
lb1.SelectedItems.Add(lb1.Items[0]);
lb1.SelectedItems.Add(lb1.Items[2]);

Form1 frm1 = new Form1(); // The receiving instance should be figured out in another way

string[] items = new string[lb1.SelectedItems.Count];

for (int counter = 0; counter < lb1.SelectedItems.Count; counter++) {
   items[counter] = lb1.SelectedItems[counter].ToString();
}

frm1.AddListboxItems(items);

Note that the receiving form is created in the code so in a real situation you probably need to have a reference to an already existing form.

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