CS50 PSET 1黑客不良信用代码 [英] CS50 PSET 1 hacker bad credit code

问题描述

目标是查找信用卡号码是否有效。

完整说明此处：

问题集1：C [ ^ ]

我能否知道是什么让我的代码失败？

（我没有运行错误）



我尝试过：

The goal is to find if a credit card number is valid.
Complete Instructions Here:
Problem Set 1: C[^]
Can I please know what makes my code fail?
(I dont get running errors)

What I have tried:

#include <stdio.h>
include <cs50.h>
include <stdlib.h>
include <ctype.h>
include <string.h>
include <math.h>
int main(void) {
char name[20]; char dist[3]; long long number = GetLongLong();
sprintf(name, "%lld", number );
int length = strlen(name);
if ( (length != 13) || (length != 15) || (length != 16) ) { printf("INVALID"); return 1; }
int SUM = 0; if ( (length == 13) || (length == 15) ) { for (int a = 1; a < length-1; a+=2) { int prodig = (name[a]-48)* 2; sprintf(dist, "%d", prodig); if (strlen(dist) == 2) { SUM = SUM + (dist[0]-48) + (dist[1]-48); } else { SUM += prodig; } }
   for (int a = 0; a < length; a+=2)
   {
       SUM += (name[a]-48);
   }
}
if (length == 16) { for (int a = 1; a < 17; a+=2) { int prodig = (name[a]-48)* 2; sprintf(dist, "%d", prodig); if (strlen(dist) == 2) { SUM = SUM + (dist[0]-48) + (dist[1]-48); } else { SUM += prodig; } }
   for (int a = 0; a < 15; a+=2)
   {
       SUM += (name[a]-48);
   }
}
if (SUM%10 != 0) { printf("INVALID"); return 1; }
else { if (name[0] == 3) { printf("AMEX"); }
   else if (name[0] == 5)
   {
       printf("MASTERCARD");
   }

   else
   {
       printf("VISA");
   }
}
return 0;
}

推荐答案

使用调试器。这就是它的一部分。

在函数的开头放置一个断点，然后仔细查看正在发生的事情。



但首先要帮自己一个忙，然后格式化你的代码，使其缩进一致 - 这样可以更容易地看到它发生了什么。

一旦你知道发生了什么，以及为什么会出错，这应该是相当明显的。

Use the debugger. That's part of what it is there for.
Put a breakpoint at the start of the function, and step through look at closely at what is going on.

But do yourself a favour first, and format your code so it's indented consistently - it makes it a lot easier to see what it happening.
It should be reasonably obvious once you get into it what is happening, and why it's going wrong.

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