如何在Windows应用程序中上传文件 [英] How to file upload in windows application

查看:77
本文介绍了如何在Windows应用程序中上传文件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

 DialogResult result = openDialog1.ShowDialog(); 
string fullpath = openDialog1.FileName;
string extension = Path.GetExtension(fullpath);

File.Copy(fullpath, @ C:\ Users \ Acer \ Documents\Visual Studio 2010 \Projects\sqlprocedure\sqlprocedure\Resources \Document\ + Filename + extension);

我尝试过:

尝试 但它采用相同的文件名。
我也无法获取路径其中复制文件位置文件保存请帮帮我。

解决方案

你可以用它来获得完整的路径。



 rfilename = openDialog1.InitialDirectory + openDialog1.FileName; 





更改下面的文件名使用

 FileInfo file =  new  FileInfo(  c:\ test.txt); 
file.Rename( test2.txt);


 DialogResult result = openDialog1.ShowDialog();
  string fullpath = openDialog1.FileName;
  string extension = Path.GetExtension(fullpath);

  File.Copy(fullpath, @"C:\Users\Acer\Documents\Visual Studio 2010\Projects\sqlprocedure\sqlprocedure\Resources\Document\" + Filename + extension);

What I have tried:

I Am try with this but it take same file name same.
I also cant get the path where  copy file location File is save please help me.

解决方案

you can use this to get full path.

rfilename = openDialog1.InitialDirectory + openDialog1.FileName;



to change file name use below

FileInfo file = new FileInfo("c:\test.txt");
file.Rename("test2.txt");


这篇关于如何在Windows应用程序中上传文件的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆