如何在案例2发生之前在案例2中进行切换 [英] How do I make a switch in C where case 2 cant happen before case 1 madem
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问题描述
让我们说:
我想在案件1发生之前使案例2无法发生。
Lets say I have:
And I want to make case 2 unable to happen before case 1 has happend.
int opt = -1;
while(opt != -1){
printf("1. for stuff. 2. for other stuff);
scanf("%d", &opt);
switch(opt){
case 1:
Randomize(vek);
break;
case 2:
sort(vek);
break;
defualt:
printf("Dont exist");
}
}
我的尝试:
What I have tried:
<pre lang="C">
typedef bool;
#define true 1
#define false 1
int opt = -1;
bool test = false;
while(opt != -1){
printf("1. for stuff. 2. for other stuff);
scanf("%d", &opt);
switch(opt){
case 1:
Randomize(vek);
test=true;
break;
if(test = true){
case 2:
sort(vek);
break;
}
defualt:
printf("Dont exist");
}
}
推荐答案
试试这个:
Try this:
while(opt != -1)
{
printf("1. for stuff. 2. for other stuff);
scanf("%d", &opt);
switch(opt)
{
case 1:
Randomize(vek);
test=true;
break;
case 2:
if(test == true)
{
sort(vek);
}
break;
default:
printf("Dont exist");
}
}
如果 c>你不能插入 code>改变开关的结构
。
开关
可以只处理最基本的条件:a变量是否与值匹配。
您需要使用 if elseif else
结构。
变量 test
要记住选项1已完成是要走的路。
这里是语言作者的C和C ++参考书的链接。注意,C是C ++的祖先,所以知道C对C ++总是有用。
C编程语言 - 维基百科,免费的百科全书 [ ^ ]
https://hassanolity.files.wordpress.com/2013/11/the_c_programming_language_2。 pdf [ ^ ]
http://www.ime.usp。 br / ~pf / Kernighan-Ritchie / C-Programming-Ebook.pdf [ ^ ]
C ++编程语言 [ ^ ]
You can't insert aif
to alter the structure of aswitch
.
Theswitch
can handle only the most basic condition: a variable match a value or not.
You need to use aif elseif else
structure.
The variabletest
to remember that option 1 is done is the way to go.
Here is links to references books on C and C++ by the authors of the languages. Note than C is the ancestor of C++, so knowing C is always useful with C++.
The C Programming Language - Wikipedia, the free encyclopedia[^]
https://hassanolity.files.wordpress.com/2013/11/the_c_programming_language_2.pdf[^]
http://www.ime.usp.br/~pf/Kernighan-Ritchie/C-Programming-Ebook.pdf[^]
C++ Programing Language[^]
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