当两个列连接时,如何在字符串agg中添加顺序。 [英] How to add order by in string agg, when two columns are concatenated.

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问题描述

SELECT string_agg(distinct a ||' - '|| b,','ORDER BY a,b)FROM table;



上面的sql给出错误



错误:   aggregate     DISTINCT  ORDER   BY 表达式必须在参数列表中出现 





如何解决问题。



我尝试过:



我试过上面的问题窗口中提到的sql。

解决方案

出现这种错误,我通常会使用一个子查询做我的脏工作。在 SQL Fiddle [^] [ ^ ],我想出了下面的SQL脚本。



  CREATE   TABLE 项目

itemid整数,
项目字符变化 50
);

INSERT INTO item(itemid,item) VALUES 1 ' 比萨饼');
INSERT INTO 项目(itemid,item) VALUES 2 ' cake'< /跨度>);
INSERT INTO 项目(itemid,item) VALUES 3 ' sandwich'< /跨度>);


选择 string_agg(itemid || ' - ' || item,' |')< span class =code-keyword> FROM
(( SELECT DISTINCT 项,itemid < span class =code-keyword> FROM
item ORDER BY itemid))t;


SELECT string_agg( distinct a || '-' || b , ',' ORDER BY a,b) FROM table;

The above sql giving error

ERROR: in an aggregate with DISTINCT, ORDER BY expressions must appear in argument list



How to resolve the issue.

What I have tried:

I have tried with above sql which mentioned in above problem window.

解决方案

With this kind of error, I typically use a subquery to do my dirty work. After playing around with this for a few minutes on SQL Fiddle[^][^], I came up with the SQL script below.

CREATE TABLE item
(
itemid integer,
item character varying(50)
);

INSERT INTO item(itemid, item)VALUES (1, 'pizza');
INSERT INTO item(itemid, item)VALUES (2, 'cake');
INSERT INTO item(itemid, item)VALUES (3, 'sandwich');


select string_agg(itemid || '-' || item,' | ') FROM ((SELECT DISTINCT item, itemid FROM item ORDER BY itemid)) t;


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