如何在此程序中打印密钥的值? [英] How can I print the value of the key in this program?
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问题描述
我是编程的初学者 如何在此程序中打印密钥的值?我也收到通知未定义的偏移量:第12行和第18行的4
我尝试过的事情:
BARCELONA, GER => BAYERN, POR = > BENFICA, < span class =code-string> ENG => CHELSIA) ;
$ TEAM = array( ESP => ATLETICO, GER => LEVERKUSEN , POR => PORTO, ENG => ARSENAL, ESP => REAL MADRID< /跨度>);
$ A = array_keys($ CHAMP);
$ B = array_keys($ TEAM);
for ($ i = 0 ; $ i < 1; $ i ++)
{
for($ j = 0; $ j< = count($ TEAM); $ j ++)
{
if($ A [$ i] == $ B [$ j])
{
shuffle($ B);
}
else
{
print_r($ B [$ j]);
}
}
}
?>
解决方案
TEAM = array( ESP => ATLETICO, GER => LEVERKUSEN, POR => PORTO, ENG => ARSENAL, ESP => REAL MADRID跨度>);
A = array_keys(
< BLOCKQUOTE> CHAMP);
i am beginner in programing How can i print the value of the key in this program? i am also getting the notice as "Undefined offset: 4 in line 12 and 18"
What I have tried:
"BARCELONA", "GER"=>"BAYERN", "POR"=>"BENFICA","ENG"=>"CHELSIA");
$TEAM = array("ESP"=>"ATLETICO", "GER"=>"LEVERKUSEN", "POR"=>"PORTO","ENG"=>"ARSENAL","ESP"=>"REAL MADRID");
$A=array_keys($CHAMP);
$B=array_keys($TEAM);
for ($i = 0; $i <1; $i++)
{
for($j=0;$j<=count($TEAM);$j++)
{
if($A[$i] == $B[$j])
{
shuffle($B);
}
else
{
print_r($B[$j]);
}
}
}
?>
解决方案
TEAM = array("ESP"=>"ATLETICO", "GER"=>"LEVERKUSEN", "POR"=>"PORTO","ENG"=>"ARSENAL","ESP"=>"REAL MADRID");
A=array_keys(
CHAMP);
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