如何使用javascripts在XML文件中按名称获取atrribute？ [英] How to get the atrribute by name in XML files with javascripts?

问题描述

我有一组课程，并且在每个课程中都提交了...每个字段都在标签中（TemplateField name =），它的标签类型为（TemplateFieldType pureName =），如下所示：

 <   pre     lang   =  xml >   -  <   class  < span class =code-keyword>>  
  -  <   TemplateDef       title   =  false   别名  = 员工 >  
  -  <  字段    relType   =  0 >  
  -  < span class =code-keyword><   TemplateField       name   =  perso      继承  =  false    description   =    >  
  -  <   fieldType        数字  =  2 >  
 <   TemplateFieldType       pureName   = 字符串    dis   =     /  >  
 <   / fieldType  >  
 <   / TemplateField  >  
 <   / fields  >  
  -  <   / class  >  

当我读到这个文件时，我需要它来获取每个类别的文件以及每个文件的类型如下：



员工



String perso



我有很多课程和很多自己的文件...但我在这里举个例子......我知道我可以通过代码获得课程名称：

< pre lang =Javascript> function myFunction（xml）{
var x，i， xmlDoc，txt;
xmlDoc = xml.responseXML;
txt = ;
x = xmlDoc.getElementsByTagName（' TemplateDef'）;
for （i = 0 ; i< x.length; i ++）{
txt + = x [i] .getAttribute（' 别名'）+ < br>;
}

我的代码中的
我得到了我班级的名字...但我怎么能得到它的文件。 ..我不知道如何从上面的xml文件中获取fileds和它的类型？



有任何方法可以按类名获取它们（例如perso）任何帮助？



我尝试过：



我上面的代码......但我需要帮助......任何帮助？

解决方案

x.childNodes [...]



示例 XML DOM getElementsByTagName（）方法 [ ^ ]

I have set of class and in every class it's filed ... each filed in tag (TemplateField name="") and it's type in tag (TemplateFieldType pureName="") like this :

<pre lang="xml">-<class>
      -<TemplateDef  title="false" alias="Employee">
          -<fields relType="0">
               -<TemplateField  name="perso"  inherited="false" description="" >
                      -<fieldType   number="2">
                           <TemplateFieldType  pureName="String" dis="" />
                     </fieldType>
                </TemplateField>
          </fields>
-</class>

I need when I read this file to get for each class it's fildes and for every fileds it's type like this :

Employee

String perso

I have a lot of class and a lot of own fileds ... But I here put an example ... I knew I can get the name of class by code :

function myFunction(xml) {
    var x, i, xmlDoc, txt;
    xmlDoc = xml.responseXML;
    txt = "";
    x = xmlDoc.getElementsByTagName('TemplateDef');
    for (i = 0; i < x.length; i++) { 
        txt += x[i].getAttribute('alias') + "<br>";
    }

in my code I get the name of my class ... But How I can to get it's fileds ... I did not knew How to get the fileds and it's type from the xml file above ?

there are any method to get them by name of class (for example "perso") any help?

What I have tried:

My code above ... But I need to help ...any help ?

解决方案

x.childNodes[...]

Example XML DOM getElementsByTagName() Method[^]

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