为什么这是不同的？ [英] Why this is different?

问题描述

string text = "aaaaaa";
float width1 = e.Graphics.MeasureString(
    text,
    new Font("calibri", 12, GraphicsUnit.Pixel)).Width;

float width2 = 0;
for (int i = 0; i < text.Length; i++)
{
    width2 += e.Graphics.MeasureString(
        text[i].ToString(),
        new Font("calibri", 12, GraphicsUnit.Pixel)).Width;
}

我想测量Chracter的大小。

为什么width2和width1不完全相同？

我怎样才能正确衡量人物？



我尝试过的事情：



这是我最好的主意...我猜。

i want to measure size of Chracter.
why width2 and width1 is not exactly same?
and how can i measure Character rightway?

What I have tried:

this is my best idea... i guess.

推荐答案

因为字符串的宽度不是除了非比例（或固定宽度）字体外，所有字符的宽度。

在固定宽度字体中，所有字符的宽度都相同，因此字符串是字符宽度乘以数字字符：

WIIIIILL

12222234

但是用比例字体：

WIIIIILL

12222234

字符不一样宽度。

这不会导致你的问题，但它开始说明为什么这是一个问题 - 因为比例字体可以有其他功能，如配对字距：

WAWAWA

121212

WAWAWA

121212

这里发生的是W和A被塞在一起因为部分W下的A适合，而不是等待它完成，并添加了一个小差距：

WAWANAWA

（还有其他效果，但这是最容易显示的）

所以你不能只是测量每个字符并假设字符串长度相同！



[edit]为可读性添加换行符[/ edit]

Because the width of a string is not the sum of the widths of all teh characters, except in non-proportional (or fixed width) fonts.
In a fixed width font all characters are the same width, so the string is the width of a character times the number of characters:
WIIIIILL
12222234
But in a proportional font:
WIIIIILL
12222234
The characters aren't the same width.
That doesn't cause your problem, but it starts to indicate why it's a problem - becuase proportional fonts can have other features, such as pair-kerning:
WAWAWA
121212
WAWAWA
121212
What happens here is that the W and the A are "tucked together" because part of the A "fits" under the W instead of waiting for it to finish and a small gap added:
WAWANAWA
(there are other effects as well, but that is the easiest to show)
So you can't just measure each character and assume the string will be the same length!

[edit]line breaks added for readbility[/edit]

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