如何编写函数来打印员工的层次结构树 [英] How do I write a function to print out a hierarchy tree of the employees

问题描述

将员工及其老板列表作为csv文件，编写一个打印出员工层级树的函数。



样本输入= Sam ，Ian，技术负责人，2009 / Ian，NULL，CEO，2007 / Fred，Sam，开发人员，2010



格式是姓名，主管，名称，年份加入



输出应该是



Ian CEO 2007



-Sam技术主管2009



- 免费开发者2010



我尝试过：

Given a list of employees and their bosses as a csv file , write a function that will print out a hierarchy tree of the employees.

Sample input = Sam, Ian, technical lead, 2009 / Ian, NULL, CEO,2007/ Fred, Sam, developer, 2010

The format is name, supervisor, designation, year of joining

The output should be

Ian CEO 2007

-Sam Technical lead 2009

--Fred Developer 2010

What I have tried:

import csv
with open("list.csv", 'r') as csv_file:
list_reader = csv.reader(csv_file, delimiter=",")
employee_list = {
    name: boss.strip() for name, boss, designation, year in list_reader}
mgrs = [k for k, v in employee_list.items() if v == '']
while mgrs:
    print ", ".join(mgrs)
    mgrs = [k for k, v in employee_list.items() if v in mgrs]

name：boss.strip（）for name，boss， list_reader中的名称，年份

ValueError：要解压的值太多

name: boss.strip() for name, boss, designation, year in list_reader}
ValueError: too many values to unpack

推荐答案

我可以很好地弄清楚该代码应该做什么。但我认为你应该使用 string.split [ ^ ]，而非 string.strip [ ^ ]。

I cannot quite figure out what that code is supposed to do. however I think you should be using string.split[^], not string.strip[^].

strq = "Sam, Ian, technical lead, 2009 / Ian, NULL, CEO,2007/Fred, Sam, developer, 2010"
def treeEmployee(infoStr):
	str1 = infoStr.split("/")
	s2 = []
	for i in str1:
		s2.append(i.split(","))
	for i in range(len(s2)):
		for j in range(1, len(s2)):
			if s2[i][1] == s2[j][0]:
				s2[i], s2[j] = s2[j], s2[i]
	return s2

可以我们这样做？

Can we do it this way?

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