如何反序列化此XML [英] How do I deserialize this XML

问题描述

我已经尝试了所有我可以反序列化这个XML但是根本不起作用

I've tried everything i could to deserialize this XML but doesn't work at all

<?xml version="1.0" encoding="utf-8"?>
<people>
    <root>
      <getusers>
        <IMAGE>name1.png</IMAGE>
        <ID>1</ID>
    	<SUCCESS>TRUE</SUCCESS>
      </getusers>
      <getusers>
        <IMAGE>name2.png</IMAGE>
        <ID>2</ID>
    	<SUCCESS>FALSE</SUCCESS>
      </getusers>
    </root>
</people>

任何帮助都会非常感激！



-



我尝试了什么：

Any help would be really appreciated !

-N

What I have tried:

public class getusers
{
    public string IMAGE;
    public string ID;
    public string SUCCESS;
}


string xml = File.ReadAllText ( @"D:\l.xml" );


XmlRootAttribute xRoot = new XmlRootAttribute ();
xRoot.ElementName = "people";
xRoot.IsNullable = true;

var xmlSerializer = new XmlSerializer ( typeof ( getusers [] ) , xRoot );
            
using (TextReader textReader = new StringReader(xml))
{
   res = (getusers []) xmlSerializer.Deserialize(textReader);
}

推荐答案

试试这个

try this

using System;
using System.Collections.Generic;
using System.IO;
using System.Xml.Serialization;


public class People
{
    [XmlArray("root")]
    [XmlArrayItem("getusers")]
    public List<getusers> Users { get; set; }
}

public class getusers
{
    public string IMAGE;
    public string ID;
    public string SUCCESS;
}
class TestPointer
{
    public static void Main()
    {

        string xml = File.ReadAllText(@"D:\l.xml");
        XmlRootAttribute xRoot = new XmlRootAttribute();
        xRoot.ElementName = "people";
        xRoot.IsNullable = true;
        var xmlSerializer = new XmlSerializer(typeof(People), xRoot);
        using (TextReader textReader = new StringReader(xml))
        {
            var people = (People)xmlSerializer.Deserialize(textReader);
            getusers[] result = people.Users.ToArray();
        }
    }
}

由于WCF和DataContract以及DataMember出现，我只使用它。此代码将起作用：

Since WCF and DataContract and DataMember came along, I use it exclusively. This code will work:

using System.Collections.Generic;
using System.Runtime.Serialization;

namespace YourNameSpace
{
    [DataContract(Namespace="")]
    public class People
    {
        [DataMember]
        public List<Person> Persons { set; get; }

        public People() { }
    }

    [DataContract(Namespace="")]
    public class Person
    {
        [DataMember]
        public int Id { set; get; }

        [DataMember]
        public string ImageFilePath { set; get; }

        [DataMember]
        public bool Success { set; get; }

        public Person(int id, string imagefilepath, bool success)
        {
            Id = id;
            ImageFilePath = imagefilepath;
            Success = success;
        }
    }
}

如何使用它来读取包含序列化XML的字符串：

How to use it to read a string containing the serialized XML:

// required references:
using System.IO;
using System.Runtime.Serialization;
using System.Xml;
using System.Text;  // enable StringBuilder use

// in some Method or EventHandler
People people1 = new People();

people1.Persons = new List<Person>
{
   new Person(1, "image1", true),
   new Person(2, "image2", false)
};

// serialize to string Type
StringBuilder sb = new StringBuilder();

using (XmlWriter writer = XmlWriter.Create(sb))
{
    dcs.WriteObject(writer, people1);
}

string people_xml = sb.ToString();

序列化输出将如下所示：

The serialized output will look like this:

<People xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
	<Persons>
		<Person>
			<ID>1</ID>
			<IMAGE>image1</IMAGE>
			<SUCCESS>true</SUCCESS>
		</Person>
		<Person>
			<ID>2</ID>
			<IMAGE>image2</IMAGE>
			<SUCCESS>false</SUCCESS>
		</Person>
	</Persons>
</People>

假设您在名为'people_xml的字符串变量中有上述XML输出：you ca n在内存中读到这样的内容：

Assume you have the above XML output in a string variable named 'people_xml: you can read that into memory like this:

// in some Method or EventHandler
DataContractSerializer dcs = new DataContractSerializer(typeof(People));

People readPeople;

using (var reader = XmlReader.Create(new StringReader(people_xml)))
{
    readPeople = (People) dcs.ReadObject(reader);
}

注意：



1.必需的Class DataContract属性，带有可选的'NameSpace参数[DataContract（NameSpace =） ）]设置为空字符串意味着生成的XML不会将当前的NameSpace写入其中：这使得XML在您没有NameSpace信息的上下文中可用。

Notes:

1. the required Class DataContract Attribute with the optional 'NameSpace argument [DataContract(NameSpace = "")] set to an empty string means the resulting XML will not have the current NameSpace written into it: this makes the XML usable in contexts where you do not have that NameSpace information.

检查这个out： XML序列化和反序列化：第2部分 [ ^ ]

Check this out: XML Serialization and Deserialization: Part-2[^]

这篇关于如何反序列化此XML的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！